The two bulges are called tidal bulges. There are two
tidal bulges on opposite sides of Earth. One is beneath the moon and the
other is opposite to that. The one below the moon is thought of as gravitational.
It is produced by gravitational attraction between water molecules in the ocean
and the moon.
<span>Now, about the other bulge. Think about inertia and what
happens when masses rotate around a single point. Imagine yourself
swinging a bucket of any liquid with your arm in a circular gesture. Even as
the bucket goes over your head, the water is still held in the bucket and
doesn't splash all over you. This rotation creates a centrifugal force. A
similar event occurs during the lunar month as the earth/moon system rotates. The
moon orbits the earth, but the rotation axis for this orbit isn't earth's
center. Both the moon and Earth move during the roughly 28-day period it takes
for the orbit, and because of this, water in the ocean is thrown to the
outside, the same as the water in your bucket. The tidal bulge on the opposite
side of Earth from the moon is produced by this inertial effect, referred to as
centrifugal force.</span>
Answer:
Value of n in MnSO₄.nH₂O is one.
Explanation:
The n represents the number of moles of water attached to the formula unit manganese sulfate. These moles (n) can be determined by taking the ratio of the moles of anhydrous salt and the moles of water. The moles of water can be determined by taking the difference of final and initial mass of the salt. This difference is equal to the mass of the water, mathematically it can be represented as,
Mass of H₂O = initial mass of the salt (g) - final mass of the salt (g)
Mass of H₂O = 16.260 g - 14.527 g
Mass of H₂O = 1.733 g
moles of H₂O = (1.733 g) ÷ (18.015 g/mole)
moles of H₂O = 0.0962
For the moles of anhydrous salt:
moles of MnSO₄ = mass of MnSO₄ ÷ molar mass of MnSO₄
moles of MnSO₄ = 14.5277 ÷ 151.001
moles of MnSO₄= 0.0962
Now for n:
n = moles of water ÷ moles of MnSO₄
n = 0.0962 ÷ 0.0962
n = 1
The above calculations show that one mole of H₂O is attached to the one formula unit of MnSO₄
The number of moles hydrogen produced when 6 moles of sodium are used is calculated as below
2Na + 2H2O = 2NaOH +H2
by use of mole ratio between Na to H2 which is 2:1 the moles of H2 is therefore
= 6 x1/2 = 3 moles of H2
<span>1. 5.6 L of NO2(g)
2. 7.5 L of H2(g)
3. 11.2 L of N2(g)
4. 22.4 L of CO(g)</span>