We dissolve 2.45 g of sugar in 200.0 g water. what is the mass percent of sugar in the solution?
2 answers:
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Answer : The correct option is, (A) 300.0 mL of 0.10 M CaCl₂
Explanation :
<u>(a) 300.0 mL of 0.10 M CaCl₂</u>
The dissociation reaction will be:
To calculate the number of moles of CaCl₂ as :
As, 1 mole of CaCl₂ contains ions = 3
So, 0.03 mole of CaCl₂ contains ions = 0.03 × 3 = 0.09 ions.
<u>(b) 400.0 mL of 0.10 M NaCl</u>
The dissociation reaction will be:
To calculate the number of moles of NaCl as :
As, 1 mole of NaCl contains ions = 2
So, 0.04 mole of NaCl contains ions = 0.04 × 2 = 0.08 ions.
<u>(c) 200.0 mL of 0.10 M FeCl₃</u>
The dissociation reaction will be:
To calculate the number of moles of FeCl₃ as :
As, 1 mole of FeCl₃ contains ions = 4
So, 0.02 mole of FeCl₃ contains ions = 0.02 × 4 = 0.08 ions.
<u>(d) 800.0 mL of 0.10 M sucrose</u>
The dissociation of sucrose is not possible because it is a non-electrolyte.
To calculate the number of moles of sucrose as :
As, 1 mole of sucrose contains ions = 1
So, 0.08 mole of sucrose contains ions = 0.08 × 1 = 0.08 ions.
Hence, the solutions contains the greatest number of ions is, 300.0 mL of 0.10 M CaCl₂