I got your answer! I will tell you right now. Your GCF is 9 and your LCM is 180! Your very much welcome!! Good luck for you! :)
Since the data is insufficient. Let us denote that n1 = 100, n2 = 100X1 = 38. X2 = 40
So looking for the p value:
p = (38+ 40) / (100 + 100) = 0.39
z = (38/100 - 40/100)/√ (0.39*(1-0.39)*(1/100 + 1/100))= -0.2899
P-value = P (|z| > 0.2899) = 0.7718
Step-by-step explanation:
I hope it helps man this much .
Answer:
2nd option
Step-by-step explanation:
Under a reflection in the x- axis
a point (x, y ) → (x, - y ) , then
P (- 8, 1 ) → P' (- 8, - 1 )
Q (- 6, - 8 ) → Q' (- 6, 8 )
R (4, - 3 ) → R' (4, 3 )
