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seraphim [82]
2 years ago
10

Anne takes a rectangular piece of fabric and cuts from one corner to the opposite corner. If the piece of fabric is 15 inches lo

ng and 8 inches wide, how long is the diagonal cut that Anne made ?
Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
5 0

\sqrt{5^2+18^2}=

\sqrt{349}=

18.68154...

You might be interested in
7) What is/are the center,
o-na [289]

Answer:

center: (0,0)

vertices: (-4,0) and (4,0)

foci: (-10.8,0) and (10.8,0)

asymptotes: y = -5/2*x and y = 5/2*x

Step-by-step explanation:

Hyperbola with center as origin general equation is:

x²/a² - y²/b² = 1

Our equation is:

25x² - 4y² = 400

Dividing each term by 400:

25x²/400 - 4y²/400 = 400/400

x²/16 - y²/100 = 1

which matches the general equation. Then, the center is (0,0)

a² = 16

a = 4

b² = 100

b = 10

c² = a² + b²

c = √(16+100) = 10.8

General vertices formula: (±a,0). Replacing, the vertices are: (-4,0) and (4,0)

General foci formula: (±c,0). Replacing, the foci are: (-10.8,0) and (10.8,0)

General asymptotes formula: y = ±b/a*x. Replacing, the asymptotes are:

y = -10/4*x = -5/2*x

y = 10/4*x = 5/2*x

3 0
3 years ago
Can you guys help me with this please???
almond37 [142]

Answer:

y=-25x+225

Step-by-step explanation:

The slope is -25 and I think the y-intercept is 225.

Hope this helps.

5 0
3 years ago
Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
7 0
3 years ago
Write the exponential function for the following geometric sequence:
Luden [163]

Step-by-step explanation:

I think the answer should be y = 36 ( 3x) as the numbers in the sequence are being divide by 3

7 0
3 years ago
HELP!! What is the approximate measure of angle x in the triangle shown?
Alex Ar [27]
<h3>Answer:   D)  130.5 degrees</h3>

=================================================

Work Shown:

c^2 = a^2 + b^2 - 2*a*b*\cos(C)\\\\10^2 = 5^2 + 6^2 - 2*5*6*\cos(x)\\\\100 = 25 + 36 - 60*\cos(x)\\\\100 = 61 - 60*\cos(x)\\\\100 - 61 = - 60*\cos(x)\\\\39 = - 60*\cos(x)\\\\\cos(x) = \frac{39}{-60}\\\\\cos(x) = -0.65\\\\x = \arccos(-0.65)\\\\x \approx 130.5416\\\\x \approx 130.5\\\\

Note: I used the law of cosines. Make sure your calculator is in degree mode.

6 0
3 years ago
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