The given question describes a right triangle with with one of the angles as 20 degrees and the side adjacent to the angle 20 degrees is of length 5,000 feet. We are looking for the length of the side opposite the angle 20 degrees.
Let the required length be x, then
![\tan{20^o}=\cfrac{opp}{hyp}=\cfrac{x}{5,000}\\ \\ \Rightarrow x=5,000\tan{20^o}=1,819.85](https://tex.z-dn.net/?f=%20%5Ctan%7B20%5Eo%7D%3D%5Ccfrac%7Bopp%7D%7Bhyp%7D%3D%5Ccfrac%7Bx%7D%7B5%2C000%7D%5C%5C%20%5C%5C%20%5CRightarrow%20x%3D5%2C000%5Ctan%7B20%5Eo%7D%3D1%2C819.85%20)
Therefore, the height of the airplane above the tower is 1,819.85 feet.
Answer: 105 meters
Step-by-step explanation:
Ostrich's running rate is 63 meters/3 seconds. This can be reduced to 21 meters/second (21 m/s).
(21 m/s)*(5 sec) = 105 meters
Answer is C!
Ok I got to organize the info...
3/15 and 12/55
3*2...
Aha
3*4 equals 12 but not 15...
A: No
B:
8/24 12/35
No
GAUTIE
Sorry...
It's C
5/18 = 25/90
5*5=25
18*5 = 90
Hope that helps you!
One more happy customer!
<3
Answer:
![P(X = 0) = 0.0263](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%200.0263)
![P(X = 1) = 0.1407](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%200.1407)
![P(X = 2) = 0.3012](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%200.3012)
![P(X = 3) = 0.3224](https://tex.z-dn.net/?f=P%28X%20%3D%203%29%20%3D%200.3224)
![P(X = 4) = 0.1725](https://tex.z-dn.net/?f=P%28X%20%3D%204%29%20%3D%200.1725)
![P(X = 5) = 0.0369](https://tex.z-dn.net/?f=P%28X%20%3D%205%29%20%3D%200.0369)
Step-by-step explanation:
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
In this problem we have that:
![n = 5, p = 0.517](https://tex.z-dn.net/?f=n%20%3D%205%2C%20p%20%3D%200.517)
Distribution
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20C_%7B5%2C0%7D.%280.517%29%5E%7B0%7D.%280.483%29%5E%7B5%7D%20%3D%200.0263)
![P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B5%2C1%7D.%280.517%29%5E%7B1%7D.%280.483%29%5E%7B4%7D%20%3D%200.1407)
![P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%20C_%7B5%2C2%7D.%280.517%29%5E%7B2%7D.%280.483%29%5E%7B3%7D%20%3D%200.3012)
![P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224](https://tex.z-dn.net/?f=P%28X%20%3D%203%29%20%3D%20C_%7B5%2C3%7D.%280.517%29%5E%7B3%7D.%280.483%29%5E%7B2%7D%20%3D%200.3224)
![P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725](https://tex.z-dn.net/?f=P%28X%20%3D%204%29%20%3D%20C_%7B5%2C4%7D.%280.517%29%5E%7B4%7D.%280.483%29%5E%7B1%7D%20%3D%200.1725)
![P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369](https://tex.z-dn.net/?f=P%28X%20%3D%205%29%20%3D%20C_%7B5%2C5%7D.%280.517%29%5E%7B5%7D.%280.483%29%5E%7B0%7D%20%3D%200.0369)
Answer:
$11.20
Step-by-step explanation:
Another Answer is futile