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Pie
3 years ago
10

URGENT PLS RESPOND!!!

Mathematics
1 answer:
Elan Coil [88]3 years ago
6 0

Answer:

\huge\boxed{d=\sqrt{17}}

Step-by-step explanation:

Simply use the fact that the change in x squared + the change in y squared = the distance squared.  (The Pythagorean Theorem)

1^2 + 4^2 = d^2

1 + 16 = d^2

17 = d^2

d = √17

Hope it helps :)

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Quadrilateral ABCD is dilated by a scale factor of 3/2 to create quadrilateral A'B'C'D'. If quadrilateral ABCD has an area of 30
kow [346]

Answer:

67.5

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, rotation, reflection and dilation.

Dilation is the enlargement or reduction of an object by a factor.

The area of ABCD = AB * BC = 30

As a result of the dilation to form A'B'C'D', A'B' = 3/2 * AB, B'C' = 3/2 * BC, C'D' = 3/2 * CD and A'D' = 3/2 * AD. Hence:

Area of A'B'C'D' = A'B' * B'C' =  3/2 * AB * 3/2 * BC = 9/4 * (AB * BC) = 9/4 * 30 = 67.5

5 0
3 years ago
Davis is buying a new car for $21,349.00.He plans to make a down payment of $3,000.00.If he's to make monthly payments of $352 f
nekit [7.7K]
He actually borrowed P=21349-3000=18349 (present value)
Assume the monthly interest is i.
then future value due to loan:
F1=P(1+i)^n=18349(1+i)^(5*12)=18349(1+i)^60
future value from monthly payment of A=352
F2=A((1+i)^n-1)/i=352((1+i)^60-1)/i
Since F1=F2 for the same loan, we have
18349(1+i)^60=352((1+i)^60-1)/i
Simplify notation by defining R=1+i, then
18349(R^60)-352(R^60-1)/(R-1)=0
Simplify further by multiplication by (R-1)
f(R)=18349*R^60*(R-1)-352(R^60-1)=0
Solve for R by trial and error, or by iteration to get R=1.004732
The APR is therefore
12*(1.004732-1)=0.056784, or 5.678% approx.




8 0
3 years ago
WILL GIVE BRAINLIEST, THANKS, AND 5 STARS!<br> PLEASE HELP ME!
Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

<u>Method 1</u>

Apply Difference of Two Squares Formula: a^2-b^2=(a+b)(a-b)

Given  x^2-16=0

Rewrite 16 as 4²

Therefore, a^2=x^2 and b^2=4^2

\implies a = \sqrt{x^2}=x

\implies b=\sqrt{4^2} =4

\implies x^2-16^2=(x+4)(x-4)

\implies (x+4)(x-4)=0

\implies (x+4)=0 \implies x=-4

\implies (x-4)=0 \implies x=4

<u>Method 2</u>

Given equation:

x^2-16=0

Add 16 to both sides:

\implies x^2-16+16=0 + 16

\implies x^2=16

Square root both sides:

\implies \sqrt{x^2}=\sqrt{16}

\implies x=\pm4

Therefore, x = -4, x = 4

6 0
2 years ago
Sketch a graph of y=2x
stealth61 [152]
Y-int, x=0
y = 2(0) therefore y-int is (0,0)
x-int, y=0
0=2x
x = 0 therefore x-int is (0,0)
4 0
4 years ago
Read 2 more answers
4 1/3 x 4 2/5 simplify
Artemon [7]

Answer:

I am pretty sure that the answer is 19 1/15! Hope this helps!!!!!!

3 0
3 years ago
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