Find the value of the variable
2 answers:
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The length and width of the rectangle are 7.90 inches and 31.6 inches respectively
It is given that,
Let the length of the rectangle = l
Let the width of the rectangle = w
The perimeter of the rectangle = 250 inches
l x w = 250 ....eq 1
Then,
Length is 4 times as big as width
4l = w
We need to find, the length and width of the rectangle
Putting the value of w in eqn 1
We get,
Similarly, we can get,
w = 4l
w = 4 x 7.90
w = 31.6
Hence, the length and width of the rectangle are 7.90 inches and 31.6 inches respectively
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Answer:
Step-by-step explanation:
Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.
(Two tailed test for variance )
Sample variance =480
We can use chi square test for testing of hypothesis
Test statistic =
p value = 0.0100
Since p <0.05 our significance level, we reject H0.
The sample variance cannot be claimed as equal to 300.