Please answer for me domain and range

Norm has $15,000 to deposit. His daughter is a junior in high school and plans to go to college. Recommend the best way for Norm

galina1969 [7]

Answer:

A money market account paying 3.5% interest, renewable for three-month commitments.

6 0

3 years ago

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In 2014, 85 percent of households in the United States had a computer. For a randomly selected sample of 200 households in 2014,

DochEvi [55]

Answer:

The mean of C is 170 households

The standard deviation of C, is approximately 5 households

Step-by-step explanation:

The given parameters are;

The percentage of households in the United States that had a computer in 2014 = 85%

The size of the randomly selected sample in 2014, n = 200

The random variable representing the number of households that had a computer = C

Therefore, we have;

The probability of a household having a computer P = 85/100 = 0.85

Let

Therefore;

The mean (expected) number in the sample, μₓ, = E(x) = n × P is given as follows;

μₓ = 200 × 0.85 = 170

The mean of C = μₓ = 170

The variance, σ² = n × P × (1 - P) = 200 × 0.85 × (1 - 0.85) = 25.5

Therefore;

The standard deviation, σ = √(σ²) = √(25.5) ≈ 5.05

The standard deviation of C, σ ≈ 5 households (we round (down) to the nearest whole number)

7 0

3 years ago

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A 8:1 scale was used to create a 27 in. by 17 in. scale drawing of a credit card for a company's new marketing campaign. The com

SOVA2 [1]

Answer:

175

or it is 5636.7

Step-by-step explanation:

2 inches x 10 miles = 200 miles - 3 inches = 175

or

10 * 563.67 = 5636.7

3 0

3 years ago

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How to evaulate the expression using order of operations

Tcecarenko [31]

<h3>Order of Operations: </h3><h3>The steps used to evaluate a numerical expression:</h3><h3> 1) Simplify the expressions inside grouping symbols. ( ) , [ ]</h3><h3>2) Evaluate all powers. </h3><h3>3) Do all multiplications and/or divisions from left to right. </h3><h3>4) Do all additions and/or subtractions from left to right. </h3><h3>PEMDAS represents the order of operations: Parentheses, Exponents, Multiplication/Division, Addition/Subtraction</h3><h2>Example :</h2><h3>18 – (4 + 2) + (6 × 5) ÷ 3 = [Parentheses first]</h3><h3>Notice: There are no Exponents in this expression. </h3><h3>18 – 6 + 30 ÷ 3 = [Multiplication/Division left to right next] </h3><h3>18 – 6 + 10 = 22 [Addition/Subtraction left to right next]</h3><h3>When there are multiple grouping symbols, always work on the innermost grouping symbols first </h3><h3> ( ) = Parentheses [ ] = Brackets</h3><h3>Example: [(7 – 2) × 3] ÷ [4 + (2 ÷ 2)] – 7 × 0</h3><h3>Start with [(7 – 2)] and (2 ÷ 2) as these are the operations in the innermost grouping symbols.</h3><h3> </h3>

5 0

3 years ago

Suppose a consumer product researcher wanted to find out whether a highlighter lasted longer than the manufacturer's claim that

rosijanka [135]

Answer:

C) t = 2.635; p = 0.006; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last longer than 14 hours.

Step-by-step explanation:

Data given and notation

$\bar X=14.5$ represent the sample mean

$s=1.2$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =14$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 14, the system of hypothesis would be:

Null hypothesis: $\mu \leq 14$

Alternative hypothesis: $\mu > 14$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{14.5-14}{\frac{1.2}{\sqrt{40}}}=2.635$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.635)=0.006$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis

The best option would be:

C) t = 2.635; p = 0.006; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last longer than 14 hours.

4 0

3 years ago