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Margarita [4]
2 years ago
15

Process of producing salt from sea water

Chemistry
1 answer:
andrew-mc [135]2 years ago
5 0

Answer:

evaporating

Explanation: evaporating the seawater in a pot when the water evaporates the salt remains in the pot.

I hope this helps :)

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If 2 or more elements are involved in a chemical reaction, they will most likely form a/an
wlad13 [49]

the correct answer would be mixture because compound uses the same element

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3 years ago
Water (2350 g ) is heated until it just begins to boil. If the water absorbs 5.83×105 J of heat in the process, what was the ini
Eva8 [605]

Answer:

40.7062 °C  

Explanation:

Let the initial temperature = x °C

Boiling temperature of water = 100 °C

Using,

Q = m C ×ΔT

Where,  

Q is the heat absorbed in the temperature change from x °C to 100 °C.

C gas is the specific heat of the water = 4.184 J/g  °C

m is the mass of water

ΔT = (100 - x) °C  

Given,

Mass = 2350 g

Q = 5.83 × 10⁵ J

Applying the values as:

Q = m C ×ΔT

5.83 × 10⁵ = 2350 × 4.184 × (100 - x)

<u>x, Initial temperature = 40.7062 °C  </u>

3 0
3 years ago
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anyanavicka [17]
I believe that the answer is A. Decaying
7 0
3 years ago
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Does a substance that heats up quickly have a high or a low specific heat capacity
Oliga [24]
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4 0
3 years ago
Nitrogen monoxide, NO, is formed in automobile exhaust by the reaction of nitrogen and oxygen in the air: N2 (g) + O2 (g) ↔ NO (
Solnce55 [7]

Answer:

The equilibrium concentration of NO is 0.001335 M

Explanation:

Step 1: Data given

The equilibrium constant Kc is 0.0025 at 2127 °C

An equilibrium mixture contains 0.023M N2 and 0.031 M O2,

Step 2: The balanced equation

N2(g) + O2(g) ↔ 2NO(g)

Step 3:  Concentration at the equilibrium

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[O2] = 0.031 M

Kc = 0.0025 = [NO]² / [N2][O2]

Kc = 0.0025 = [NO]² / (0.023)(0.031)

[NO] = 0.001335 M

The equilibrium concentration of NO is 0.001335 M

6 0
3 years ago
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