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2 answers:
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Answer:
See picture for answer
Explanation:
At the beggining, we know that X is a secondary alcohol, with 3 carbons. The only secondary alcohol with 3 carbons, it's the isopropylic alcohol (or 2-propanol). So, in strong acid conditions, we are actually dehidrating the alcohol, to form an alkene, and then it's oxidized to form either a Ketone or aldehyde.
So in picture 1, you have all three compounds, and the mechanism of reaction to form Y.
This is an incomplete question.
The complete question is:
1,1-dichlorotetrafluoroethane, CF3CCL2F, has a vapor pressure of 228 torr. What mass of 1,1-dichloroethane must be mixed with 100.0 g of 1,1-dichlorotetrafluoroethane to give a solution with vapor pressure 157 torr at 25 degrees celsius?
Answer: 46.9 g of 1,1 dichloroethane must be fixed with 100 g of 1,1 dichlorotetrafluoroethane to give a solution with vapor pressure of 157 torr at
Explanation:
As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.
The formula for relative lowering of vapor pressure will be,
where,
= relative lowering in vapor pressure
i = Van'T Hoff factor = 1 (for non electrolytes)
= mole fraction of solute
=
Given : x g of solute is present in 100 g of solvent
moles of solute (1,1 DICHLOROEHTANE) =
moles of solvent (1,1 DICHLOROTETRAFLUOROEHTANE ) =
Total moles = moles of solute + moles of solvent =
= mole fraction of solute =
Thus 46.9 g of 1,1 dichloroethane must be fixed with 100 g of 1,1 dichlorotetrafluoroethane to give a solution with vapor pressure of 157 torr at