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2 years ago

Help i give 5 stars and a crown

Mathematics

1 answer:

REY [17]2 years ago

6 0

Answer:

See below.

Step-by-step explanation:

1a)

Angles:

48, 90, 90, a.

Add:

48 + 90
= 138 + 90
= 228

Subtract:

360 - 228
= 132.

Angle a: 132.

1b)

To get angle h above 180°, We need to add h + 164:

h + 164
= 110 + 164
= 274.

h = 110.

This is how to get h over 180°.

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The common minimum multiple between A) 2,3 and 6 B) 8,9 and 12 C) -4,2 and 8

Elan Coil [88]

A 2,3 and 6. There you go. :)

8 0

3 years ago

Tell whether -2 is a solution of the inequality n-5<8

ruslelena [56]

Answer:

-2 is a solution

Step-by-step explanation:

-2-5<8

-7<8

6 0

3 years ago

Edg vector operations, any help appreciated!

viktelen [127]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c$

____________________________________

$\large \tt Solution \: :$

Vector d can be represented as :

$\qquad \tt \rightarrow \: - 2 \hat i - 2 \hat j$

Vector c can be represented as :

$\qquad \tt \rightarrow \: 4 \hat i + 4\hat j$

we have to create vector d from vector c

So, let's assume a vector x, such that sum of vector x and vector c equals to vector d

$\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) = - 2 \hat i - 2 \hat j$

$\qquad \tt \rightarrow \: x = - ( 4 \hat i + 4 \hat j) - 2 \hat i - 2 \hat j$

$\qquad \tt \rightarrow \: x = (- 4 \hat i - 2 \hat i) + ( - 4 \hat j - 2 \hat j)$

$\qquad \tt \rightarrow \: x = - 6 \hat i -6 \hat j$

Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

2 years ago

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

The estimate is $- 0.0265\le K \le 0.0465$

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

3 0

3 years ago

What's 45x10 to the power of 8923 -12 x2342 / 92123

PtichkaEL [24]

Answer:

umm here..i don't know if it's right but there....you can download mathpapa and goodluck

8 0

3 years ago

Help i give 5 stars and a crown​

Help i give 5 stars and a crown