Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
Ok so, the quotient of a number y and 22, we would solve this problem like this... y:22, and y:22 is equal to 7/22, therefore, the quotient of a number y and 22 would be.
Step-by-step explanation:
We know that,
![Z=\dfrac{X-\mu}{\sigma}](https://tex.z-dn.net/?f=Z%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D)
Where,
X = raw score = 84
μ = mean = 68
σ = standard deviation = 10
Putting the values,
![Z=\dfrac{84-68}{10}=1.6](https://tex.z-dn.net/?f=Z%3D%5Cdfrac%7B84-68%7D%7B10%7D%3D1.6)
The percent of his sales that were less than or equal to 84 inches, is
![P(Z\leq 1.6)=0.9452=94.52\%\approx 94.5\%](https://tex.z-dn.net/?f=P%28Z%5Cleq%201.6%29%3D0.9452%3D94.52%5C%25%5Capprox%2094.5%5C%25)
Therefore, the remaining 100-94.5=5.5% were more than 84 inches.
Multiply each dimension by 35:-
17*35 = 595 cm
18*35 = 630 cm
19.7 * 35 = 689.5 cm
in meters the dimensions are L = 6.895 m, W = 6.3 m and H = 5.95 m
The height of the trapezoid is 2 cm