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2 years ago

Five squares are positioned as shown. The small square indicated has area 1 . What is the value of h?

Mathematics

1 answer:

shepuryov [24]2 years ago

4 0

Answer:

Step-by-step explanation:

Each box is 1 larger than the earlier one, so the boxes are 1, 2, 3, 4, and 5.

4 + 5 is the width across the bottom

2 + 3 is the width across the top (not counting h)

9 - 5 = 4, so h = 4

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<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

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<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

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➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

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➙The roots of a quadratic equation ax + bx + c = 0 are given by $\sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}}$ provided b - 4ac ≥ 0.

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here as per the given quadratic equation,

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$\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}$

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$\implies\sf{x=\frac{1 + \: 7}{4}}$

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$\implies{\boxed{\bf{x=2}}}$

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$\implies\sf{x=\frac{1 - \: 7}{4}}$

$\implies\sf{x=\frac{-6}{4}}$

$\implies{\boxed{\bf{x=\frac{-3}{2}}}}$

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<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

Hope it helps!! (:

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Answer:

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