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yulyashka [42]
3 years ago
10

Circumference and area of a circle (picture provided)

Mathematics
1 answer:
Anestetic [448]3 years ago
4 0

Answer:

B

Step-by-step explanation:

The formulas we need are below:

C=dπ

A=r²π

d=2r

Plug in the values.

d=12

C=12π

A=36π

C=12(3.14)=37.68

A=36(3.14)=113.04

B matches

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Determine if each of the following sets is a subspace of Pn, for an appropriate value of n.
snow_tiger [21]

Answer:

1) W₁ is a subspace of Pₙ (R)

2) W₂ is not a subspace of Pₙ (R)

4) W₃ is a subspace of Pₙ (R)

Step-by-step explanation:

Given that;

1.Let W₁ be the set of all polynomials of the form p(t) = at², where a is in R

2.Let W₂ be the set of all polynomials of the form p(t) = t² + a, where a is in R

3.Let W₃ be the set of all polynomials of the form p(t) = at² + at, where a is in R

so

1)

let W₁ = { at² ║ a∈ R }

let ∝ = a₁t² and β = a₂t²  ∈W₁

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t²) + c₂(a₂t²)

= c₁a₁t² + c²a₂t²

= (c₁a₁ + c²a₂)t² ∈ W₁

Therefore c₁∝ + c₂β ∈ W₁ for all ∝, β ∈ W₁  and scalars c₁, c₂

Thus, W₁ is a subspace of Pₙ (R)

2)

let W₂ = { t² + a ║ a∈ R }

the zero polynomial 0t² + 0 ∉ W₂

because the coefficient of t² is 0 but not 1

Thus W₂ is not a subspace of Pₙ (R)

3)

let W₃ = { at² + a ║ a∈ R }

let ∝ = a₁t² +a₁t  and β = a₂t² + a₂t ∈ W₃

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t² +a₁t) + c₂(a₂t² + a₂t)

= c₁a₁t² +c₁a₁t + c₂a₂t² + c₂a₂t

= (c₁a₁ +c₂a₂)t² + (c₁a₁t + c₂a₂)t ∈ W₃

Therefore c₁∝ + c₂β ∈ W₃ for all ∝, β ∈ W₃ and scalars c₁, c₂

Thus, W₃ is a subspace of Pₙ (R)

8 0
3 years ago
The monthly income of a government servant is Rs 77,280 and he gets the festival expense of one month's salary, what is his taxa
kifflom [539]

I don't think this question is complete but here's ur answer

5 0
2 years ago
A neighbor farmer had some chickens. She had 24 feet of wire fencing to
Paraphin [41]

Answer:

A rectangle is defined by its length = L, and its width = W.

So the perimeter of the of the rectangle can be written as:

Perimeter = 2*L + 2*W.

In this case, we want to leave the perimeter fixed, so we have:

24ft = 2*L + 2*W.

Now, we do not have any other restrictions, so to know the different dimensions now we can write this as a function, by isolating one of the variables.

2*L = 24ft - 2*W

L = 12ft - W.

or:

L(W) = 12ft - W.

Such that:

W must be greater than zero (because we can not have negative or zero width).

And W must be smaller than 12ft (because in that case we would have zero or negative length)

Then the possible different dimensions are given by:

L(W) = 12ft - W

0ft < W < 12ft.

8 0
3 years ago
*not drown to scale
bulgar [2K]

Answer:

26.9 inches

Step-by-step explanation:

2x Pythagorean theorem

First we find the length of AC with ABC. AC is the hypotenuse of triangle ABC.

AC = sqrt(7^2+24^2) = sqrt625 = 25.

Now, AD is the hypotenuse of ACD. So AD = sqrt(25^2+10^2) = sqrt(725) = 26.925824 which is about 26.9 inches.

8 0
2 years ago
Read 2 more answers
carson walks his dog 6 blocks south to the park. Next they jog 5 blocks east to go swimming at the pond. How many blocks did car
Vinil7 [7]

Pretty simple, 5 + 6 = 11 blocks total

4 0
3 years ago
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