Question:
1. The females worked less than the males, and the female median is close to Q1.
2. There is a high data value that causes the data set to be asymmetrical for the males.
3. There are significant outliers at the high ends of both the males and the females.
4. Both graphs have the required quartiles.
Answer:
The correct option is;
1. The females worked less than the males, and the female median is close to Q1
Step-by-step explanation:
Based on the given data, we have;
For males
Minimum = 0
Q1 = 1
Median or Q2 = 20
Q3 = 25
Maximum = 50
For females;
Minimum = 0
Q1 = 5
Median or Q2 = 6
Q3 = 10
Maximum = 18
Therefore, the values of data that affect the statistical measures of spread and center are that
The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range
Also the female median is very close to Q1, therefore it affects the definition of a measure of center.
Answer:
48 in
Step-by-step explanation:
The length of the rug is 6 feet. We know this must account for 2 sides of the rug, so let's multiply 6 by 2.
6 × 2 = 12
Now subtract 12 from 20.
20 - 12 = 8
Now divide 8 by 2 to find the measurement of the remaining two sides.
8 ÷ 2 = 4.
The width of the rug is 4 feet. The question wants to find the width in inches, however. So multiply 4 by 12 because there are 12 inches in each foot.
4 × 12 = 48
The width of the rug is 48 inches.
the answer in standard form is 10+3
1 bag per 5 minutes.
If you divide 15(total amount of min) by 3(bags of popcorn you popped) you will see you popped 1 bag per 5 minutes.
Now its say per minutes, then, you will have to say 1/5 bag per minutes.
Answer:
b.
Step-by-step explanation:I think
