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Airida [17]
3 years ago
11

Help me please I will give brainiest​

Mathematics
1 answer:
nadya68 [22]3 years ago
8 0
8.a)
A= (1,1) A’= (3,3)
B= (4,6) B’= (12,18)
C= (6,1). C= (18,3)

8b.)

A= (1,1) A’(0,5,0.5)

B= (4,6) B(2,3)

C= (6,1). C(3,0.5)


Hope this helped ! :)
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I forgot how to do this n they didn’t put an example help me lol
lyudmila [28]

Answer:

60m^2

Step-by-step explanation:

First, find the area of the square as it the missing piece wasn't missing.

    8 x 9 = 72m^2

Then, find the area of the missing section.

    3 x 4 = 12m^2

Finally, subtract 12m^2 from 72m^2 and you get 60m^2

3 0
3 years ago
The school play is selling tickets for their new show. Adult tickets cost $10 while child tickets cost 5$. Their goal is to earn
DaniilM [7]
If an adult ticket costs $10, and a chlid's ticket is $5, then one possible combination of tickets could be 30 adult tickets and 10 children tickets. Another could be to sell 15 adult tickets and 25 children tickets.
3 0
3 years ago
The mean per capita income is 16,127 dollars per annum with a variance of 682,276. What is the probability that the sample mean
MakcuM [25]

Answer:

0.60% probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

The standard deviation is the square root of the variance. So

\mu = 16127, \sigma = \sqrt{682276} = 826, n = 476, s = \frac{826}{\sqrt{476}} = 37.86

What is the probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

Either it differs by 104 or less dollars, or it differs by more than 104 dollars. The sum of the probabilities of these events is 100. I am going to find the probability that it differs by 104 or less dollars first.

Probability that it differs by 104 or less dollars first.

pvalue of Z when X = 16127 + 104 = 16231 subtracted by the pvalue of Z when X = 16127 - 104 = 16023. So

X = 16231

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16231 - 16127}{37.86}

Z = 2.75

Z = 2.75 has a pvalue of 0.9970

X = 16023

Z = \frac{X - \mu}{s}

Z = \frac{16023 - 16127}{37.86}

Z = -2.75

Z = -2.75 has a pvalue of 0.0030

0.9970 - 0.0030 = 0.9940

99.40% probability that it differs by 104 or less.

What is the probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

p + 99.40 = 100

p = 0.60

0.60% probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

7 0
3 years ago
F(x)=-2x^2-2x+10 f(x)=−2x 2 −2x+10 \text{Find }f(2) Find f(2)
romanna [79]

Given that:

f(x) = -2x²-2x+10

f(2) = -2(2)²-2(2)+10

= -2(2*2) - 4 + 10

= -2(4) - 4 + 10

= -8 - 4 + 10

= -12 + 10

= -2 Ans.

Read more:

Similar Question

Given f(x) = 1/2x - 5, find f^-1(x) a. f^-1 (x) = -2x+10 b. f^-1(x) = 2x+5 c. f^-1(x) = 2x-10 d. f^-1(x) = 2x+10...

brainly.com/question/11148895?referrer

8 0
2 years ago
Please tell me the answer quick
Vesnalui [34]
To compare these numbers, you must first put them into one format.  Since you have mixed numbers, you may have to find and use the LCD.

-2.5, 1/5, 10, -12/4, 18/5, 10 could be simplified somewhat immediately:

-2.5, 1/5, 10, -3, (3 3/5)   This set of numbers is simple enough so that you could rearrange them in ascending order mentally:

-3, -2.5, 1/5, (3 3/5), 10

In this case the number of elements in this set is odd, so all you have to do is to select the MIDDLE element:  1/5.

The median is 1/5.

You MUST learn this procedure (arranging the set elements in ascending order and selecting the middle element) so that you can apply it yourself.

8 0
3 years ago
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