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Airida [17]
3 years ago
11

Help me please I will give brainiest​

Mathematics
1 answer:
nadya68 [22]3 years ago
8 0
8.a)
A= (1,1) A’= (3,3)
B= (4,6) B’= (12,18)
C= (6,1). C= (18,3)

8b.)

A= (1,1) A’(0,5,0.5)

B= (4,6) B(2,3)

C= (6,1). C(3,0.5)


Hope this helped ! :)
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this visual representation shows the sets of real numbers. classify the number −25. select all terms that are correct. natural w
vekshin1

-25 is an integer and a rational number.

<h3>What is number system?</h3>
  • A system of writing numbers is known as a number system.
  • It is the mathematical notation for consistently employing digits or other symbols to represent the numbers in a particular set.
  • It represents the arithmetic and algebraic structure of the numbers and gives each number a distinct representation.

Now,

  • Natural numbers are positive integers with a range of 1 to infinity; nevertheless, they do not include zero. -25 wouldn't be a natural number because it is a negative number.
  • A group of numbers known as a whole number consists of all positive integers and 0. This wouldn't be a whole number because -25 isn't a positive number.
  • Any real number that cannot be represented as the quotient of two integers is said to be irrational. Square roots of irrational numbers are also frequently seen. -25, however, is not a square root.
  • Any number that can be expressed as a ratio, or a fraction, of two integers, is referred to be a rational number. Fractions, decimals, negative decimals, and other rational numbers are very prevalent. Since -25 can be represented as a ratio of two numbers. it is a rational number.
  • A whole number that can be either positive, negative, or zero is known as an integer. As -25 is negative and a whole number( when positive), it is an integer.

Hence, -25 is an integer and a rational number.

To learn more about number system, refer to the link: brainly.com/question/13162939

#SPJ4

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Verify this trig function. <br> tanysiny = secy-cosy ?
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LHS\\ \\ =\tan { y } \sin { y } \\ \\ =\frac { \sin { y }  }{ \cos { y }  } \cdot \sin { y }

\\ \\ =\frac { \sin ^{ 2 }{ y }  }{ \cos { y }  } \\ \\ =\frac { 1-\cos ^{ 2 }{ y }  }{ \cos { y }  }

\\ \\ =\frac { 1 }{ \cos { y }  } -\frac { \cos ^{ 2 }{ y }  }{ \cos { y }  } \\ \\ =\sec { y } -\cos { y } \\ \\ =RHS
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