Help please I beg of you

John held a garage sale. He priced all the items at a dime or a quarter. His sales totaled

Nikitich [7]

John held a garage sale. He priced all the items at a dime or a quarter, his sales totaled less than $5, the solution is shaded region in quadrant I.

<h3>What is a slope?</h3>

In mathematics, line's slope, also known as its gradient, is a numerical representation of the line's steepness and direction. The letter m is frequently used to represent the slope; reason for this usage is unclear, but it can be found in O'Brien's (1844) and Todhunter's (1888) formulations of equation for a straight line as "y = mx + b" and "y = mx + c," respectively.

He priced all items at a dime or a quarter. His sales totaled less than $5

Since dime =$ 0.10=$0.10 and the quarter =$0.25=$0.25

Let x=x= the number of the items sold for a dime

Let y=y= the number of the items sold for a quarter

0.10x+0.25y<5

Inequality in the slope-intercept form

0.10x+0.25y Subtract 0.10x from both sides

0.25y<-0.10x+5 Divide both sides by 0.25

Subtract 0.10x from both sides

$y= -\frac{2}{5}x+20\\$

The slope is, $-\frac{2}{5}$ and the y- intercept is 20

Since inequality sign is << so, draw a dashed line

Test point (0,0)(0,0)

Substituting the values 0 for x and 0 for y,

$y < -\frac{2}{5}x+20\\\\0 < -\frac{2}{5}(0)+20\\\\0 < +20$

Since inequality is true

So, (0,0)(0,0) is solution of the inequality

Shade region containing (0,0)(0,0).

The graph below shows all possible solutions

Since boundary line is dashed and the number of items is always positive

The solution is shaded region in quadrant I

To know more about quadrant visit: brainly.com/question/7196312

#SPJ9

4 0

2 years ago

Part 2. State what additional information is required in order to know that the triangles are congruent by ASA.

Helga [31]

<h3>Answer: Choice D. $\angle SQR \cong \angle XQR$ </h3>

The red angle markers show those two angles are congruent. That's one "A" of "ASA". The S refers to a congruent pair of sides. We don't have any tickmarks to indicate congruent pairs; however, we do know that QR = QR is a shared side that overlaps (reflexive theorem). So this is the "S" in "ASA".

The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that $\angle SQR \cong \angle XQR$ , then we can use ASA.

One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.

7 0

3 years ago

M +9 = -3<br> 8<br> What is the answer for m

harina [27]

Answer:

m=-12

Step-by-step explanation:

Not sure where the 8 comes from, but you would subtract 9 from the left side. The result is -12.

3 0

3 years ago

Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]