Answer:
Molly's Z score for LSAT
z-score=-2
Molly's Z score for MCAT
z-score=2
Step-by-step explanation:
z-score for LSAT
Molly's score=120
mean=150
Standard deviation=15
z-score= (Molly LSAT score-mean)/standard deviation
z=120-150/15=-30/15=-2
z-score for MCAT
Molly's score=52
mean=40
Standard deviation=6
z-score= (Molly MCAT score-mean)/standard deviation
z=52-40/6=12/6=2
Answer:
Step-by-step explanation:
Answer: Rotation, Translation and Reflection
Explanation
Rotation, translation and reflection moves the shape, resulting in a congruent shape but in a different position. Dilation changes the length/width of the shape. The shape can be similar, but not congruent.
The zeroes of the polynomial functions are as follows:
- For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
- For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
- For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
<h3>What are the zeroes of a polynomial?</h3>
The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.
The polynomials are given as follows:
f(x) = 2x(x - 3)(2 - x)
f(x) = 2(x - 3)²(x + 3)(x + 1)
f(x) = x³(x + 2)(x - 1)
For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.
Learn more about polynomials at: brainly.com/question/2833285
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Since we are solving for n you have to isolate the n. Therefore, you want all the variables with an n in it on one side and all the variables without an n on the other side:) :
4k+3= -mn+n (There were a change in signs because for example you moved the -3 to the other side, therefore it can only be a negative on one side so now you have to change the sign to a positive:) hope you got that)
That would've been your answer because you cannot do anything else...Hope this helped :)