The figure consists of three objects, a rectangle, a trapezoid, a triangle
Find the area of the rectangle
The rectangle is 16 in long and 9 in wide
a₁ = l × w
a₁ = 16 × 9
a₁ = 144 in²
Find the area of the trapezoid
The base of trapezoid is 31 in and 16 in, and the height is 35 - 20 = 15 in.
a₂ = 1/2 × (a + b) × h
a₂ = 1/2 × (31 + 16) × 15
a₂ = 1/2 × 47 × 15
a₂ = 352.5 in²
Find the area of the triangle
The base of the triangle is 31 in, the height is 20 in
a₃ = 1/2 × b × h
a₃ = 1/2 × 31 × 20
a₃ = 310 in²
Add the area together
a = a₁ + a₂ + a₃
a = 144 + 352.5 + 310
a = 806.5
The answer is 806.5 in²
Answer:
If x is the distance from centre fo the circle, with radius 25cm, to its intersection point with the common chord, x²+24²=25² =>x=7cm.
Distance from this intersecting point to the centre of the other circle=39–7=32cm
Ratio of the sides of the right triangle thus formed is 24:32=3:4. Since 3:4:5 is the basic pythagorean triplet, the radius of the other circle=5*24/3=40cm.
Aliter: radius of the other circle=√32²+24²= 40cm.
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Answer:
a=1, b=9 and c= 5
Step-by-step explanation:
9/11 divided by 5/11
= 9/11 * 11/5
11 gets cancelled
=9/5
it can also be written as 1* 9/5
Hence here a=1, b=9 and c= 5
<em>Please mark me as brainliest.</em>
One of the very nice features of the metric system of measurements is that there is a set of standardized prefixes that can be applied to any of the units. Some of the more common ones are
.. micro- . . . one millionth
.. milli- . . . . one thousandth
.. centi- . . . .one hundredth
.. kilo- . . . . .one thousand
Thus, one millimeter is 1/1000 = 0.001 meter. There are 1000 of them in 1 meter, so
.. 16 m = 16000 mm
M=1-5/2-3=-4/-1=4
M=4
(3,5)
5=2(3)+b
5=6+b
b=-1
