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2 years ago

Show how to compute 3+5 using a number line

Mathematics

1 answer:

scZoUnD [109]2 years ago

5 0

Answer:

Step-by-step explanation:

divide the gap between 0 and 1 into 5 equal parts and take first 3 parts from 0

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An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of stude

AnnZ [28]

Answer:

60 students

Step-by-step explanation:

The confidence interval of a proportion is given by:

$p\pm z*\sqrt{\frac{p*(1-p)}{n} }$

Where 'p' is the proportion of students who responded 'yes', 'z' is the z-score for a 95% confidence interval (which is known to be 1.960), and 'n' is the number of students in the sample.

If the confidence interval is from 0.584 to 0.816, then:

$p=\frac{0.584+0.816}{2}=0.7 \\0.816-0.584=2*(1.96*\sqrt{\frac{p*(1-p)}{n}}) \\0.116=1.96*\sqrt{\frac{0.7*(1-0.7)}{n}}\\n=16.8966^2*(0.7*0.3)\\n=60\ students$

60 students were in the sample.

8 0

3 years ago

Can someone help me with this problem [-64x(-5)-2x(3)]

galina1969 [7]

The answer is 314
(^o^)

5 0

3 years ago

Read 2 more answers

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago

5x−13x≥16 what’s the answer

Arlecino [84]

x ≤ -2

Step-by-step explanation:

$\begin{aligned}\tt 5x-13x&\geq 16\\\tt (5-13)x&\geq\tt 16\\\tt -8x&\geq\tt 16\\\tt 8x&\leq\tt -16\\\tt x&\leq\tt\frac{-16}{8}\\\tt x&\leq\tt -2\end{aligned}$

6 0

3 years ago

Number 76 nunber 77 number 78and 79 please

Dmitry [639]

76) 10n^8

77) 35v^11

78) 2025/n^2

79) 4k^8

7 0

3 years ago