is to say
for all
beyond some fixed
.
Similarly,
is to say
for all
.
From this we can gather that
where
is the larger of the two values
and
, or
. Then the last term is bounded above by
from which it follows that
9514 1404 393
Answer:
(a) 31.5 in²
Step-by-step explanation:
The area of a rhombus is half the product of the lengths of the diagonals.
A = 1/2(d1)(d2)
A = (1/2)(7 in)(9 in) = 31.5 in²
There are 31.5 in² of space in the rhombus for engraving.
You can solve this problem by using the Gauss method. The Gauss method is a method where you can add the first and last numbers together, and then multiply by how many times that appears. Here, the sum of the first and last number is -11. In this sequence, it would appear ten times (since there are ten terms and the terms are used twice in every eleven). -11 * 5 is -55, so that means the answer to this question is -55.
Step-by-step explanation:
[tex]Another example , when a straight wire is moved up and down rapidly between the two poles of a horseshoe magnet , then an electric current is produced in the wire. This is also an example of electromagnetic induction .
Answer: B. (-6, 5)
Step-by-step explanation:
