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3 years ago

Is y= 0.25x + 4 (linear or nonlinear)

Mathematics

2 answers:

Ivanshal [37]3 years ago

8 0

Answer:

linear bro

Step-by-step explanation:

NikAS [45]3 years ago

6 0

Answer:

Linear

Step-by-step explanation:

This equation is linear because it's a straight line, and it follows the slope-intercept equation. Slope-intercept equations only work on linear functions.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

~ ren ⚘

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3 years ago

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3 years ago

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Elanso [62]

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3 years ago

A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure anti

prohojiy [21]

ANSWER

Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

To proof

let us assume that the fluid should be drained and replaced with pure antifreeze be x .

As given

A radiator contains 10 quarts of fluid, 30% of which is antifreeze.

Now write 30% in the decimal form

$= \frac{30}{100}$

Now write 60% in the decimal form

$= \frac{60}{100}$

After drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )

The quantity of antifreeze is

$= \frac{30\times (10 - x)}{100}$

The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

than the equation becomes

$= x + \frac{30\times ( 10 - x )}{100} = \frac{60\times10}{100}$

solyving

100x +300 - 30x = 600

70x = 300

$x = \frac{300}{70}$

x = 4.28 quarts (approx)

Hence 4.28 quarts (approx) fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

Therefore the option (c.) is correct .

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3 years ago

Read 2 more answers

A past survey of students taking a standardized test revealed that % of the students were planning on studying engineering in c

Angelina_Jolie [31]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The 95% confidence interval is $-0.00870$

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 1068000$

The first proportion $\r p_1 = 0.084$

The second sample size is $n_2 = 1476000$

The second proportion is $\r p_2 = 0.092$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100 - 95)\%$

$\alpha = 0.05$

From the normal distribution table we obtain the critical value of $\frac{ \alpha }{2}$ the value is

$Z_{\frac{\alpha }{2} } =z_c= 1.96$

Now using the formula from the question to construct the 95% confidence interval we have

$(\r p_1 - \r p_2 )- z_c \sqrt{ \frac{\r p_1 \r q_1 }{n_1} + \frac{\r p_2 \r q_2 }{n_2} }$

Here $\r q_1 = 1 - \r p_1$

=> $\r q_1 = 1 - 0.084$

=> $\r q = 0.916$

and

$\r q_2 = 1 - \r p_2$

=> $\r q_2 = 1 - 0.092$

=> $\r q_2 = 0.908$

$(0.084 - 0.092 )- (1.96)* \sqrt{ \frac{0.092* 0.916 }{1068000} + \frac{0.084* 0.908 }{1476000} }$

$-0.00870$

3 0

3 years ago