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noname [10]
3 years ago
10

Which of the following statements is false?

Mathematics
1 answer:
Whitepunk [10]3 years ago
6 0

Answer:

A.

Step-by-step explanation:

It's the first one. The angles are supplementary not complementary.

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A line passes through the points (-4, 3) and (0, 0). What is the slope of the line?
Katarina [22]
-3/4 let me know if you would like me to explain.
5 0
3 years ago
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P(AB) can be read as "the probability that Boccurs given that A has
anzhelika [568]

Answer:

Step-by-step explanation:

At least you know its not false

3 0
3 years ago
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A circle is centered at (-4, 6) and has a radius of 9. What is the equation of the circle? Question 3 options: (x+4)2+(y−6)2=18
Lera25 [3.4K]

Answer:

(x+4)² + (y-6)² = 81

Step-by-step explanation:

<u>General equation of a circle :</u> (x-h)² + (y-k)² = r²

where (h,k) is at center and r = radius

Here we are given that the circle has a center at (-4,6) and a radius of 9

So we have (h,k) = (-4,6) so h = -4 and k = 6 and radius = 9 so r = 9

<u>Plugging in values into general equation</u>

Recall that the general equation of a circle is (x-h)² + (y-k)² = r²

we have h = -4 , k = 6 and r = 9

==> plug in values

doing so we acquire (x-(-4))² + (y-6)² = 9²

==> apply double negative sign rule

(x+4)² + (y-6)² = 9²

==> evaluate exponent

(x+4)² + (y-6)² = 81

And we are done!

3 0
2 years ago
Can someone please help me
oksian1 [2.3K]
With what subject? what question?
8 0
4 years ago
A is the point (10,4) and B is the point (4,-6).
schepotkina [342]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{10}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{-6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{4+10}{2}~,~\cfrac{-6+4}{2} \right)\implies (7,-1) \\\\[-0.35em] \rule{34em}{0.25pt}


\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{\textit{origin}}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{0})}\qquad \stackrel{\textit{midpoint of AB}}{(\stackrel{x_2}{7}~,~\stackrel{y_2}{-1})}\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(7-0)^2+(-1-0)^2}\implies d=\sqrt{7^2+(-1)^2} \\\\\\ d=\sqrt{48}\implies d\approx 6.93

7 0
3 years ago
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