Find the factors and zeros of 6x^2 +8x-28=2x^2 + 4
1 answer:
Answer:
First solve the equation:
6x^2 + 8x -28 = 2x^2 + 4
=> 6x^2 - 2x^2 + 8x - 28 -4 = 0 => 4x^2 + 8x - 32 = 0
Extract common factor 4:
=> 4[x^2 + 2x - 8] = 0
Now factor the polynomial:
4(x + 4) (x - 2) = 0
=> the solutions are x + 4 = 0 => x = -4, and x - 2 = 0 => x = 2.
So the answer is the option B: 4(x + 4)(x - 2); {-4, 2}
HOPE THIS HELPS! :D
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Answer:
HI! I think the answer is 4.
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Its A) -67
plug the m and n values into the function and solve using pemdas.
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The U stands for union. Combine A and B
Hope that helps!!
