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earnstyle [38]
3 years ago
15

Simplify the expression by combining like terms.

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0
4b + 2 is your answer just to help you out if you use cymath you can easily get your answer like i did 

You might be interested in
Which system of equations can be used to solve for the point of intersection of the lines on the graph? A) y = x - 7; y = 2x + 2
ratelena [41]

Answer:

C) y = 2x + 7; y = 2x + 2

Step-by-step explanation:

The two lines are parallel and so will have the same slope.

From the graph, the slope of both lines are two.

Using slope intercept formula, y=mx+c, with m=2, we have y=2x+c

The blue line has a y-intercept of 2 so the equation is

y = 2x + 2

The red line has a y-intercept of -7 so the equation is

y = 2x - 7

Hence the system is

y=2x+2

y=2x-7

The correct answer is C

4 0
3 years ago
The coordinates of the endpoint of a line segments are -3, -5. The line segment is 11 units long. What are the other possible en
Anettt [7]

Answer:

8, 6.

x=8 y=6

Step-by-step explanation:

-3 + 11 = +8

-5 + 11 = +6

8 0
3 years ago
Read 2 more answers
What is the maximum number of relative extrema contained in the graph of this function f(x)=3x^3-x^2+4x-2
Sergeeva-Olga [200]
The maximum number of turning points in a cubic function is 2.

In this case,

f(x)=3x^3-x^2+4x-2\implies f'(x)=9x^2-2x+4

The discriminant is (-2)^2-4(9)(4)=-140, which means the derivative has no real roots. This means there are no critical points and thus no turning points/relative extrema.
5 0
3 years ago
Read 2 more answers
Jake can mulch a garden in 30 minutes. together, jake and ross can mulch the same garden in 16 minutes. how much time t, in minu
Gelneren [198K]

"Jake can mulch a garden in 30 minutes." So, for 1 min Jake can mulch 1/30 part of a garden.

Ross can mulch the park for x minutes. So, for 1 min Jake can mulch 1/x part of a garden.

If they work together, for 1 min they will mulch (1/30 + 1/x) part of the garden.

At the same time, we know, that of they work together they can mulch the garden in 16 min, so for 1 min they will mulch 1/16 part of the garden.

Now, we can write an equation

\frac{1}{30}  + \frac{1}{x} = \frac{1}{16}  \\ \\ \frac{1}{x} = \frac{1}{16} - \frac{1}{30}  \\ \\ \frac{1}{x} =\frac{30-16}{16*30}  \\ \\ \frac{1}{x} =\frac{14}{16*30}  \\ \\x=\frac{16*30}{14}

x≈34.3 (min)

8 0
3 years ago
Find the minimum or maximum value of the function g(x)= -(x-2)^2-3
Nady [450]
Neato

assuming you mean
g(x)=-1(x-2)^2-3
remember
in form
f(x)=a(x-h)^2+k
a is leading coficient
(h,k) is vertex
k will be the minimum or max value of the function
if a is positive, then the parabola opens up and k is minimum
if a is negative, then the parabola opens down and k is max

given
g(x)=-1(x-2)^2-3
a is negative
the parabola opens down and k is the max value
it is -3
the max value is -3, which occors at x=2
g(2)=-3 is max
3 0
3 years ago
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