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GrogVix [38]
2 years ago
9

A particle of charge Q and mass m is accelerated from rest through a potentialdifference V, attaining a kinetic energy K. What i

s the kinetic energy of a partical of charge2Q and mass m/2 that is accelerated fromrest through the same potential difference?
a) K/4
b) K/2
c) K
d) 2K
e) 4K
Physics
1 answer:
Ilia_Sergeevich [38]2 years ago
3 0

Hi there!

Recall the equation for work given a potential difference and charge:
\large\boxed{W = qV}

W = Work (J)
q = charge (C)
V = Potential difference (V)

The work is equivalent to the change in KINETIC ENERGY, and only depends on the particle's charge and the potential difference that it experiences. Mass has no impact on this.

Thus:

W' = (2Q)(V) = 2W

This is equivalent to:


\large\boxed{2W = \text{ d) } 2K}}

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Let,
m
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​
= Mass of ball A
m
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​
= Mass of ball B
u
A
​
= initial velocity of ball A
u
B
​
= initial velocity of ball B
v
A
​
= Velocity after the collision of ball A
v
B
​
= Velocity after the collision of ball B
F
ab
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= Force exerted by A on B
F
ba
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= Force exerted by B on A
Now,
Change in the momentum of A= momentum of A after the collision - the momentum of A before the collision
= m
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v
A
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−m
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u
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Rate of change of momentum A= Change in momentum of A/ time taken
=
t
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v
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​
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u
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​

Force exerted by B on A (F
ba
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F
ba
​
=
t
m
A
​
v
A
​
−m
A
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u
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​
........ [i]
In the same way,
Rate of change of momentum of B=
t
m
b
​
v
B
​
−m
B
​
u
B
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​

Force exerted by A on B (F
ab
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)=
F
ab
​
=
t
m
B
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v
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​
−m
B
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u
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​
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F
a
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a [ ' -- ' sign is used to indicate that 1 object is moving in opposite direction after collision]

Using [i] and [ii] , we have
t
m
B
​
v
B
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−m
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u
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v
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m
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v
B
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u
B
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v
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​
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