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GrogVix [38]
2 years ago
9

A particle of charge Q and mass m is accelerated from rest through a potentialdifference V, attaining a kinetic energy K. What i

s the kinetic energy of a partical of charge2Q and mass m/2 that is accelerated fromrest through the same potential difference?
a) K/4
b) K/2
c) K
d) 2K
e) 4K
Physics
1 answer:
Ilia_Sergeevich [38]2 years ago
3 0

Hi there!

Recall the equation for work given a potential difference and charge:
\large\boxed{W = qV}

W = Work (J)
q = charge (C)
V = Potential difference (V)

The work is equivalent to the change in KINETIC ENERGY, and only depends on the particle's charge and the potential difference that it experiences. Mass has no impact on this.

Thus:

W' = (2Q)(V) = 2W

This is equivalent to:


\large\boxed{2W = \text{ d) } 2K}}

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<span>L = 343 T </span>
<span>L = 343/20,000 </span>
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The correct answers would be option A, C and E.

Explanation:

A material made up of synthetic or semi synthetic compounds is called Plastic. This material is malleable and can be molded into solid form. There are many disadvantages of using the plastics. Three of the main disadvantages are :

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young modulus = 5 x 10^{9} N/m^{2}

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radius = 0.015 m

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we can get the mass from the formula below

young modulus = stress ÷ strain

where

stress = \frac[force}{area} = \frac {mass x g}{area}

area = 2πr = 2π x 0.015 = 0.094

therefore    

young modulus = \frac{\frac {mass x g}{area}}{strain}

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Let \vec u and \vec v be the vectors, and let x=\|\vec u\|=\|\vec v\| be their common magnitude.

The resultant \vec u + \vec v is \sqrt 2 times larger in magnitude than either vector alone, so \|\vec u+\vec v\| = \sqrt2\,x.

Recall the dot product identity

\vec a \cdot \vec b = \|\vec a\| \|\vec b\| \cos(\theta)

where \theta is the angle between the vectors \vec a and \vec b. In the special case of \vec a=\vec b, we get

\vec a \cdot \vec a = \|\vec a\|^2 \cos(0^\circ) \implies \|\vec a\| = \sqrt{\vec a\cdot\vec a}

Now, to get the angle between \vec u and \vec v, we have

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