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Vsevolod [243]
4 years ago
13

The equation E = MC squared relates energy and 1. Force 2. Gravity 3. Mass 4. Work

Physics
2 answers:
Sladkaya [172]4 years ago
8 0
The equation relates Energy to mass
Ganezh [65]4 years ago
7 0
The equation relates energy to mass
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A portable CD player uses two 1.5 volt batteries. if the current in the CD player is 2amps ,what is resistance?
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resistance=voltage/current

1.5/2=0.75ohms

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A boat is travelling due west at a speed of 47 miles per hour. If the boat started off 170 miles directly north of the city of S
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A backpack has a mass of 8 kg. It is lifted and given 54.9 J of gravitational potential energy. How high is it lifted? Accelerat
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Potencial Energy=hma
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Two point charges of +20.0 μC and -8.00 μC are separated by a distance of 20.0 cm. What is the intensity of electric field E mid
algol13

Answer:

The intensity of the net electric field will:

E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C

Explanation:

Here we need first find the electric field due to the first charge at the midway point.

The electric field equation is given by:

|E_{1}|=k\frac{q_{1}}{d^{2}}

Where:

  • k is Coulomb's constant
  • q(1) is 20.00 μC or 20*10⁻⁶ C
  • d is the distance from q1 to the midpoint (d=10.0 cm)

So, we will have:

|E_{1}|=(9*10^{9})\frac{20*10^{-6}}{0.1^{2}}

|E_{1}|=1.8*10^{7}\: N/C

The direction of E1 is to the right of the midpoint.

Now, the second electric field is:

|E_{2}|=k\frac{q_{2}}{d^{2}}

|E_{2}|=(9*10^{9})\frac{8*10^{-6}}{0.1^{2}}

|E_{2}|=7.2*10^{6}\: N/C

The direction of E2 is to the right of the midpoint because the second charge is negative.

Finally, the intensity of the net electric field will:

E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C

I hope it helps you!

5 0
3 years ago
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