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Vsevolod [243]
4 years ago
13

The equation E = MC squared relates energy and 1. Force 2. Gravity 3. Mass 4. Work

Physics
2 answers:
Sladkaya [172]4 years ago
8 0
The equation relates Energy to mass
Ganezh [65]4 years ago
7 0
The equation relates energy to mass
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3. When two liquids are mixed and a solid
sashaice [31]

Answer:

D

Explanation:

6 0
3 years ago
When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 43.
zmey [24]

To solve this problem, we must take two important steps. First we will convert all the given units, to international system. Later we will define the torque, which is given as the product between the radius of application of the force and the Force acting on the body. Mathematically the latter is,

\tau = r F

Here,

r = Radius

F = Force

Now the units,

r = 1.95cm = 1.95*10^{-2}m

Replacing,

\tau = (1.95*10^{-2})(43.5N)

\tau = 0.8483N\cdot m

Therefore the torque that the muscle produces on the wrist is 0.85N\cdot m

3 0
3 years ago
In a Rutherford scattering experiment a target nucleus has a diameter of 1.34×10-14 m. The incoming α particle has a mass of 6.6
Rasek [7]

Answer:

E = 2.5 x 10⁻¹⁴ J

Explanation:

given,

diameter = 1.33 x 10⁻¹⁴ m

mass = 6.64 x 10⁻²⁷ kg

wavelength is equal to diameter

de broglie wavelength equal to diameter

         \lambda = \dfrac{h}{mv}

         1.33 \times 10^{-14}= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times v}

         v= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times 1.33 \times 10^{-14}}

              v = 7.5 x 10⁶ m/s

Kinetic energy is equal to

     E = \dfrac{1}{2}mv^2

     E = \dfrac{1}{2}\times 6.64 \times 10^{-27}\times (7.5\times 10^6)^2

            E = 2.5 x 10⁻¹⁴ J

8 0
3 years ago
Two large, flat, horizontally oriented plates are parallel to each other, a distance d apart. Half-way between the two plates th
fgiga [73]

Answer:

Explanation:

Let the potential difference between the plate is V . Then in the first case

Electric field E between plate

E₁ = V / d

where d is separation between plate

When the plate separation becomes d / 2

Electric field E between plate

E₂ = V / d /2

= 2 V / d =2E₁

Or twice the earlier field

5 0
4 years ago
!!!!!!PLEASE HELP ASAP !!!!!!!!!!!!
OLga [1]

Answer: d constint speed

Explanation: im 15 and no the answer

5 0
3 years ago
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