Question

A proton, mass 1.67 · 10 27 kg and charge +1.6 · 10 19 C, moves in a circular orbit perpendicular to a uniform magnetic field of 0.71 T. Find the time for the proton to make one complete circular orbit.

Answer 1

Answer:

Time, $T=9.23\times 10^{-8}\ s$

Explanation:

It is given that,

Mass of proton, $m=1.67\times 10^{-27}\ kg$

Charge on proton, $q=1.6\times 10^{-19}$

Magnetic field, B = 0.71 T

Time taken by proton to make one complete circular orbit is given by :

$T=\dfrac{2\pi m}{qB}$

$T=\dfrac{2\pi \times 1.67\times 10^{-27}}{1.6\times 10^{-19}\times 0.71}$  

$T=9.23\times 10^{-8}\ s$  

So, the time for the proton to make one complete circular orbit is  $9.23\times 10^{-8}\ s$. Hence, this is the required solution.