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kvv77 [185]
2 years ago
5

Homework 2 , help jim !

Mathematics
1 answer:
statuscvo [17]2 years ago
8 0

Problem 4, part (a)

<h3>Answer:  \triangle\text{L}\text{B}\text{M}</h3>

Explanation:

Notice that \frac{\text{A}\text{B}}{\text{L}\text{B}} = \frac{60}{24} = 2.5 and \frac{\text{B}\text{C}}{\text{B}\text{M}} = \frac{32+48}{32} = 2.5; both ratios are equal to 2.5

The two triangles have the common overlapped or shared angle at \text{A}\text{B}\text{C}, which is identical to angle \text{L}\text{B}\text{M}.

Therefore, we can use the SAS similarity theorem to prove triangle \text{A}\text{B}\text{C} is similar to triangle \text{L}\text{B}\text{M}.

===========================================

Problem 4, part (b)

<h3>Answer: AC and LM</h3>

Explanation:

Similar triangles have congruent corresponding angles.

Since \triangle ABC \sim \triangle LBM, we know that \angle CAB \cong \angle MLB. These corresponding angles then lead to AC being parallel to LM. Refer to the converse of the corresponding angles theorem.

===========================================

Problem 4, part (c)

If we want to prove that the triangles are all similar using SSS, then we need all three of the following statements to be true

\frac{\text{A}\text{B}}{\text{N}\text{M}} = 2.5

\frac{\text{B}\text{C}}{\text{M}\text{C}} = 2.5

\frac{\text{A}\text{C}}{\text{N}\text{C}} = 2.5

Unfortunately, the reality is that  \frac{\text{A}\text{B}}{\text{N}\text{M}} = \frac{60}{35} \approx 1.71 doesn't match with the 2.5; so the three triangles are definitely not similar. We need to change NM = 35 to NM = 24 so that we have similar triangles. We just copy what segment LB shows.

------------

If instead you wanted to use SAS, then we would need NM = 24 like earlier. Also, we would need angle ABC = angle NMC to be true. Lastly, we need MC = 32 so it matches up with MB = 32.

------------

If you want to use the AA similarity rule, then we need these statements below to be true

\angle \text{A}\text{B}\text{C} \cong\angle \text{N}\text{M}\text{C}\\\angle \text{A}\text{C}\text{B} \cong\angle \text{N}\text{C}\text{M}\\\angle \text{C}\text{A}\text{B} \cong\angle \text{C}\text{N}\text{M}\\

As you can see, there are few pathways we can take to prove the triangles similar.

===========================================

Problem 5

<h3>Refer to the screenshot below. </h3>

I've filled out the table with the correct items.

You are correct to start with the given statement, which is how <u>all</u> proofs start off.

On the complete opposite end of the spectrum, the last statement will be what we want to prove. Which is namely that \triangle \text{A}\text{C}\text{E} \sim \triangle \text{B}\text{C}\text{D}, i.e. that those triangles are similar.

So somehow we have to connect the given to the thing we want to prove at the end.

Notice that angles \text{C}\text{B}\text{D} and \text{C}\text{A}\text{E} are corresponding angles. They are congruent because of the parallel lines. So we'll have \angle \text{C}\text{B}\text{D} \cong \angle \text{C}\text{A}\text{E} for statement 2. Using identical logic, we will also have \angle \text{C}\text{D}\text{B} = \angle \text{C}\text{E}\text{A} for statement 3. Both statements 2 and 3 use the reasoning of "corresponding angles are congruent". Keep in mind that the statement in quotes is only true when we have parallel lines like this.

Lastly, we'll use the AA similarity theorem to fully prove what we want, which is that \triangle \text{A}\text{C}\text{E} is similar to triangle \triangle\text{B}\text{C}\text{D}.

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The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg
julia-pushkina [17]

Answer:

Approximately 101\; \rm ft (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

  • Let \rm O denote the observer.
  • Let \rm A denote the top of the tree.
  • Let \rm R denote the base of the tree.
  • Let \rm B denote the point where line \rm AR (a vertical line) and the horizontal line going through \rm O meets. \angle \rm B\hat{A}R = 90^\circ.

Angles:

  • Angle of elevation of the base of the tree as it appears to the observer: \angle \rm B\hat{O}R = 51^\circ.
  • Angle of elevation of the top of the tree as it appears to the observer: \angle \rm B\hat{O}A = 57^\circ.

Let the length of segment \rm BR (vertical distance between the base of the tree and the base of the hill) be x\; \rm ft.

The question is asking for the length of segment \rm AB. Notice that the length of this segment is \mathrm{AB} = (x + 20)\; \rm ft.

The length of segment \rm OB could be represented in two ways:

  • In right triangle \rm \triangle OBR as the side adjacent to \angle \rm B\hat{O}R = 51^\circ.
  • In right triangle \rm \triangle OBA as the side adjacent to \angle \rm B\hat{O}A = 57^\circ.

For example, in right triangle \rm \triangle OBR, the length of the side opposite to \angle \rm B\hat{O}R = 51^\circ is segment \rm BR. The length of that segment is x\; \rm ft.

\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}.

Rearrange to find an expression for the length of \rm OB (in \rm ft) in terms of x:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}.

Similarly, in right triangle \rm \triangle OBA:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}.

Equate the right-hand side of these two equations:

0.810\, x \approx 0.649\, (x + 20).

Solve for x:

x \approx 81\; \rm ft.

Hence, the height of the top of this tree relative to the base of the hill would be (x + 20)\; {\rm ft}\approx 101\; \rm ft.

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Marina86 [1]

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7

Step-by-step explanation:

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The measure of one angle is 7 times the measure of its COMPLIMENT. Find the measure of each angle.
solong [7]

Step-by-step explanation:

given,

the complete angle is complementry angle which is 90°

let the first angle be x and second angle be 7x ( as second angle is 7 times more than first angle )

now,

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therefore

1st angle = x = 11.25°

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Step-by-step explanation:

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