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SIZIF [17.4K]
3 years ago
6

How to solve: 3*9^(2n) = (3^(n +1))^3

Mathematics
2 answers:
vova2212 [387]3 years ago
8 0
3×9
n+1
−9×3
2n

​


=
3×3
2n+3
−(3
2
)
n+1

3×(3
2
)
n+1
−3
2
×3
2n

​


=
3
1+2n+3
−3
2n+2

3
1+2n+2
−3
2+2n

​


=
3
4+2n
−3
2n+2

3
3+2n
−3
2+2n

​


=
3
2n
(3
4
−3
2
)
3
2n
(3
3
−3
2
)
​


=
81−9
27−9
​


=
72
18
​


=
4
1
​
mixer [17]3 years ago
3 0

Answer:

3

Step-by-step explanation:

3*9^(2n) = (3^(n +1))^3

= 3×9^0^3

= 3×9^0

= 3×1

= 3

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8 0
4 years ago
The ages of three friends are consecutive integers. The sum of their ages is 45
Alborosie

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- 3

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