2 years ago

How to solve: 3*9^(2n) = (3^(n +1))^3

2 answers:

8 0

3×9
n+1
−9×3
2n

=
3×3
2n+3
−(3
2
)
n+1

3×(3
2
)
n+1
−3
2
×3
2n

=
3
1+2n+3
−3
2n+2

3
1+2n+2
−3
2+2n

=
3
4+2n
−3
2n+2

3
3+2n
−3
2+2n

=
3
2n
(3
4
−3
2
)
3
2n
(3
3
−3
2
)

=
81−9
27−9

=
72
18

=
4
1

mixer [17]2 years ago

3 0

Answer:

Step-by-step explanation:

3*9^(2n) = (3^(n +1))^3

= 3×9^0^3

= 3×9^0

= 3×1

= 3

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