<h2>
Answer:</h2>
<u>Distance = 360.55 m</u>
<u>Direction = North-East</u>
<h2>
Step-by-step explanation:</h2>
In the question,
The adventurous dog starts from O, say.
He moves 3 blocks East = 300 m
then,
2 blocks North = 200 m
1 block East = 100 m
1 block North = 100 m
2 blocks West = 200 m
So,
Distance of the Dog's <u>final position</u> from the <u>initial position</u><u>.</u>
OE is given by,
In triangle OLE, using Pythagoras theorem,

<em><u>Therefore, the distance of Dog from the Home is 360.55 m and the direction of Dog from Home is North-East.</u></em>
Answer:-5
Step-by-step explanation:
i could be wrong i used my calculator
Answer:
1/4 < 5/4
Step-by-step explanation:
Since the numbers have the same denominator, we compare the numerators
1<5
so 1/4 < 5/4
Answer:
I really don't get what you're asking but in finding the new area 20 feet and 10 feet I found the area and the perimeter 14 cm2. I have found both perimeter and area so if you wanted an answer I guess it is in one of my answers.
Answer:

Step-by-step explanation:
<u><em>The complete question is</em></u>
A chef bought $17.01 worth of ribs and chicken. Ribs cost 1.89 per pound and chicken costs 0.90 per pound. The equation 0.90 +1.89r = 17.01 represents the relationship between the quantities in this situation.
Show that each of the following equations is equivalent to 0.9c + 1.89r = 17.01.
Then, explain when it might be helpful to write the equation in these forms.
a. c=18.9-2.1r. b. r= -10÷2c+9
we have that
The linear equation in standard form is

where
c is the pounds of chicken
r is the pounds of ribs
step 1
Solve the equation for c
That means ----> isolate the variable c
Subtract 1.89r both sides

Divide by 0.90 both sides

Simplify

step 2
Solve the equation for r
That means ----> isolate the variable r
Subtract 0.90c both sides

Divide by 1.89 both sides

Simplify

therefore
The equation
is equivalent
The equation is helpful, because if I want to know the number of pounds of chicken, I just need to substitute the number of pounds of ribs in the equation to get the result.