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Ganezh [65]
3 years ago
14

PLEASE HURRY!!!!!!!

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0

Answer:

The mid-point of the given line segment is:(5.5,-6.5)

Step-by-step explanation:

let us consider two points A and B with coordinates (a,b) and (c,d) respectively.

let C be the mid point of A and B then then the coordinates of C is given by (\frac{a+c}{2},\frac{b+d}{2}).

in the given question (a,b)=(9,-8) and (c,d)=(2,-5) so the mid point of these two points are (\frac{9+2}{2},\frac{-8-5}{2})=(5.5,-6.5)

Hence, the coordinates of the midpoint of the line segment with endpoints B(9,-8) and C(2,-5) is (5.5,-6.5).

Vikki [24]3 years ago
7 0

( (9 + 2 ) / 2 , ( -8 + -5 ) / 2 )  =

 

<span>(  11/2 , -13/2 )</span>

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Find the area of the triangle with the given base and height.<br> b = 3 m and h = 10 1/2 m
svetoff [14.1K]

<u>Statement</u><u>:</u>

The base of a triangle is 3m and its height is 10 \frac{1}{2} m.

<u>To </u><u>find </u><u>out:</u>

The area of the triangle.

<u>Solution:</u>

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\sf \: area \:  \:  of \:  \: a \:  \: triangle =  \frac{1}{2}  \times base \:  \times height

  • Therefore, the area of the triangle

\sf =  (\frac{1}{2}  \times 3 \times 10 \frac{1}{2} ) {m}^{2}  \\ \sf  = ( \frac{1}{2}  \times 3 \times  \frac{21}{2} ) {m}^{2}  \\  = \sf  \frac{63}{4}  {m}^{2}  \\  =   \sf 15\frac{3}{4}  {m}^{2}

<u>Answer</u><u>:</u>

The area of the triangle is \sf \: 15 \frac{3}{4}  {m}^{2}

Hope you could understand.

If you have any query, feel free to ask.

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Step-by-step explanation:

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