Answer:

Step-by-step explanation:
The distance d between a point (m , n ) and a line in the form
Ax + By + C = 0 , is calculated as
d = 
Here (m, n ) = (6, 2 ) and
6x - y = - 3 ( add 3 to both sides )
6x - y + 3 = 0 → A = 6, B = - 1, C = 3
d = 
= 
= 
=
× 
=
← cancel 37 on numerator/ denominator
= 
Cylinder volume = PI * radius^2 * height
cylinder volume = 3.14159 * 16 * 4
cylinder volume = 3.14159 * 64
cylinder volume =
<span>
<span>
<span>
201.06</span></span></span>
Rewrite 9 1/6 divided by 5/6 as follows:
55 6
---- * -----
6 5
Reducing this produces the desired quotient, 11.
Answer:
The length of the line segment UV is 76 units
Step-by-step explanation:
In a triangle, the line segment joining the mid-points of two sides is parallel to the third side and equal to half its length
In Δ ONT
∵ U is the mid-point of ON
∵ V is the mid-point of TN
→ That means UV is joining the mid-points of two sides
∴ UV // OT
∴ UV =
OT
∵ UV = 7x - 8
∵ OT = 12x + 8
∴ 7x - 8 =
(12x + 8)
→ Multiply the bracket by 
∵
(12x + 8) =
(12x) +
(8) = 6x + 4
∴ 7x - 8 = 6x + 4
→ Add 8 to both sides
∴ 7x - 8 + 8 = 6x + 4 + 8
∴ 7x = 6x + 12
→ Subtract 6x from both sides
∴ 7x - 6x = 6x - 6x + 12
∴ x = 12
→ Substitute the value of x in the expression of UV to find it
∵ UV = 7(12) - 8 = 84 - 8
∴ UV = 76
∴ The length of the line segment UV is 76 units
(30/100)(90*3+50*4)
(30/100)(270+200)
(30/100)(470)
$141.00