The answer is C.37— following the picture, you know the blue angle and the green angles are supplements (add up to 180) so you add them and set them to 180 and solve. This solves out to be 37
The first term is
−
17
and the common difference is
3
Answer:
392
Step-by-step explanation:
Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.
Extend lines XQ, YR, YS and XP and mark their intersection as A and B.
Quadrilateral XAYB is a square because all right triangles PXQ, QAR, RYS and SBP are congruent (by ASA postulate) and therefore
- all angles of the quadrilateral XAYB are right angles
- all sides of XAYB are congruent and equal to 6 + 8 = 14 units.
Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20 ⇒ 2nd answer
Step-by-step explanation:
Let us revise the types of solutions of a system of linear equations
- One solution
- No solution when the coefficients of x and y in the two equations are equal and the numerical terms are different
- Infinitely many solutions when the coefficients of x , y and the numerical terms are equal in the two equations
∵ y = -2x + 5
- Add 2x to both sides
∴ 2x + y = 5 ⇒ (1)
∵ -5y = 10x + 20
- Subtract 10x from both sides
∴ -10x - 5y = 20
- Divide both sides by -5
∴ 2x + y = -4 ⇒ (2)
∵ The coefficient of x in equation (1) is 2
∵ The coefficient of x in equation (2) is 2
∴ The coefficients of x in the two equations are equal
∵ The coefficient of y in equation (1) is 1
∵ The coefficient of y in equation (2) is 1
∴ The coefficients of y in the two equations are equal
∵ The numerical term in equation (1) is 5
∵ The numerical term in equation (2) is -4
∴ The numerical terms are different
From the 2nd rule above
∴ No solution of the system of equations
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20
Learn more:
You can learn more about the system of equations in brainly.com/question/6075514
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