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polet [3.4K]
2 years ago
10

Perform the operation (9x^2+6x-7)+(-9x-5)

Mathematics
1 answer:
asambeis [7]2 years ago
8 0

Answer:

9x^{2}-3x-12

9x^{2}+6x-7-9x-5

(Group liked terms)

9x^{2}+6x-9x-7-5

( subtract the numbers ) -7-5= -12

9x^{2}+6x-9x-12

( add similar elements ) 6x-9x=-3x

9x^{2}-3x-12

Step-by-step explanation:

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I rlly need some help please if ur big brains im going to be asking multiple questions right now
Lynna [10]

You can break the shape up into a rectangle and a right triangle.

Use your trig ratios to find the missing sides.

Add all the sides up and you have your perimeter!

//

p = 2(l) + 2(w)

p = 2(10)  + 2(4)

p = 28

//

tan =  \frac{opp}{adj}

\tan(45) =  \frac{10}{adj}

adj =  \frac{10}{ \tan(45) }

adj = 10

{a}^{2}  +  {b}^{2}  =  {c}^{2}

{10}^{2}  + 10 {}^{2}  =  {200}^{2}

\sqrt{200} = 14.14213562

//

p = 10 + 4 + (4 + 10) + 14.14213562

<em>*notice how one of the 10 is left out because it is inside the shape so we can't use that to find perimeter.</em>

p = 42.14

3 0
2 years ago
In the paper drive, 4 boys brought old papers to school as follows: Fred, 30 pounds; Albert, 40 pounds; Henry, 10 pounds; and Pe
seraphim [82]
B: 30 pounds is the correct answer
5 0
3 years ago
Read 2 more answers
Relations expressed as ordered pairs are?
romanna [79]
The relations are domain and range
5 0
3 years ago
I need help with 19 20 21
lord [1]
19) 5c+c=-6+2
      6c=-4
      c=-4/6
      c=-2/3

20) -20-8=-2e
       -28=-2e
       28/2=e
      14=e

21)p-2w=2l
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5 0
2 years ago
What is the sum of two numbers a and b decreased by their product?
belka [17]

The sum of two numbers a and b decreased by their product is (a+b)-ab

Step-by-step explanation:

Given the two numbers as a and b

Sum of these two numbers is a+b

The product of the two numbers is a*b, ab

The sum of the two numbers decreased by their product will be;

(a+b)-ab

Learn More

  • https://brainly.in/question/6082654
  • https://brainly.in/question/6940394

Keywords : sum of two numbers, product

#LearnwithBrainly

8 0
3 years ago
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