We know that y is equal to x-2. We can just substitute x-2 for y since y is equal to it.
10x- 9(x-2)=24
Distribute.
10x- 9x+18= 24
x+18= 24
Subtract 18 on both sides.
x= 6
Now, plug in x.
y= (6)-2
y= 4
We can check this to see if this works:
4= 6-2, 4=4
10(6)- 9(4)= 24
60-36= 24, 24=24
x=6 and y=4
I hope this helps!
<em>~kaikers</em>
Answer:
c
Step-by-step explanation:
Answer:
This quadratic equation has 2 solutions.
Step-by-step explanation:
I assume the '?' in your question is meant to be power 2 (²), or else it would not be a quadratic equation. You could write it using the superscript version of 2.
We can solve this equation by expressing it in the form: ax² + bx + c
x² + 9x= -8
x² + 9x + 8 = 0
Now if you know the discriminant, you can simply plug in your values of a, b, and c to see how many solutions there are.
In this case, you would not need the discriminant as there are whole-number factors and hence this can simply be factorised.
x² + 9x + 8 = 0
(x + 8)(x + 1) = 0
For this equation to be true (= 0), x can equal -8 OR -1.
Hence, this quadratic equation has 2 solutions.
Answer:
25.5
Step-by-step explanation:
first find the area od the rectangle than the triangle.
to find the area count the number of squares and use A=b*h
than do the same for the triangle using A=.5*b*h
15=3*5
10.5=.5*3*7
10.5+15=25.5
Let the number of ride tickets = x tickets.
And the total cost is given by y.
Fair charges $1.25 per ticket for the rides.
Johnny bought = 25 tickets.
Therefore, cost of 25 tickets @ $1.25 per ticket = 25 × 1.25 = $31.25
Total amount spent at the fair = $43.75.
Fair admission charge = Total amount spent - Cost of 25 tickets = 43.75 - 31.25 =$12.50.
Therefore, total cost of the fair = Fix fair admission charge + total cost of x number of tickets @1.25 each.
y = 12.50 + 1.25x.
Therefore, y = 12.50 + 1.25x is the linear equation that can be used to determine the cost for anyone who only pays for x ride tickets and $ 12.50 fair admission.
