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3 years ago

1. What are the two postulates, or main ideas, that Albert Einstein based his theory of relativity on

Physics

1 answer:

Natali [406]3 years ago

3 0

1. the laws of physics are the same and can be stated in their simplest form in all inertial frames of reference

2. the speed of light is a constant, independent of the relative motion of the source.

Explanation:

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Use 4 to 5 complete sentences, explain the concepts of beats and how beats are produces.

Wewaii [24]

Answer:

Beats is a phenomenon which occurs when two sound waves with different frequencies overlap each other.

Explanation:

When these two sound waves overlap, a third frequency is formed. The places where the two waves reinforces each other, constructive interference takes place and a louder sound is produced whereas, at points where destructive interference takes place a softer sound is produced.

These alternative loud and soft sounds are called beats.

3 0

4 years ago

Help me please- T^T. just put like 1 for the first and what fields go with it

r-ruslan [8.4K]

Answer:

2 objects with steel or iron

3 objects with mass

Explanation:

8 0

3 years ago

Read 2 more answers

A police car on the side of the road (at rest) uses a radar gun to catch speeders as they approach it. The frequency the radar g

oee [108]

Answer:

$\Delta f = 1.49 \times 10^9 Hz$

Explanation:

Apparent frequency that is received to the speeder is given as

$f_1 = f_0\frac{v + v_o}{v}$

$f_1 = (8 \times 10^9)\frac{340 + v_o}{340}$

here we know that

$v_o = 65 mph = 29 m/s$

now we have

$f_1 = (8 \times 10^9)\frac{340 + 29}{340}$

$f_1 = 8.68 \times 10^9 Hz$

now the frequency that is received back from the speeder is given as

$f_2 = f_1\frac{v}{v- v_o}$

$f_2 = (8.68 \times 10^9}\frac{340}{340 - 29}$

$f_2 = 9.49 \times 10^9 Hz$

So difference is the frequency is given as

$\Delta f = 9.49 \times 10^9 - 8 \times 10^9$

$\Delta f = 1.49 \times 10^9 Hz$

4 0

3 years ago

Unpolarized light shines pon a photocell for one hour. then, two polarizers, whose transmission axies are offset by 60, are plac

LenaWriter [7]

Answer:

t = 1.10 h

Explanation:

For this exercise we must calculate the intensity that reaches the cell with the polarizers, for this we use Malus's law

I = I₀ cos² θ

Let's calculate

I = I₀ cos² 60

I = I₀ 0.907

This is the intensity that reaches the cell

To find time, use an inverse proportion rule or rule of three, the intensity Io in

t = I₀ / (0.907 I₀) 1 h

t = 1.10 h

8 0

3 years ago

Two identical particles, each with a mass of 4.5 mg and a charge of 30 nC, are moving directly toward each other with equal spee

e-lub [12.9K]

Answer:

r₁ = 20.5 cm

Explanation:

In this exercise we can use the conservation of energy

the gravitational power energy is always attractive, the electrical power energy is repulsive if the charges are of the same sign

starting point.

Em₀ = U_g + U_e + K = $-G \frac{m_1m_2}{r} +k \frac{q_1q_2}{r} - 2 ( \frac{1}{2} m v^2)$

the two in the kinetic energy is because they are two particles

final point. When it is detained

Em_f = U_g + U_e = $-G \frac{m_1m_2}{r_1} + k \frac{q_1q_2}{r_1}$

the energy is conserved

Em₀ = em_f

the charges and masses of the two particles are equal

$-G \frac{m^2}{r} + k \frac{q^2}{r} + m v^2 = - G \frac{m^2}{r_1} + k \frac{q^2}{r_1}$

sustitute the values

-6.67-11 (4.5 10-3) ² / 0.25 - 9, 109 (30 10-9) ² / 0.25 + 4.5 10-3 4² = - 6.67 10- 11 (4.5 10-3) ² / r1 -9 109 (30 10-9) ² / r1

-5.4 10⁻¹⁵ + 3.24 10⁻⁵ - 7.2 10⁻⁵ = -1.35 10⁻¹⁵ / r₁ + 8.1 10⁻⁶ / r₁

We can see that the terms that correspond to the gravitational potential energy are much smaller than the terms of the electric power, which is why we depress them.

3.24 10⁻⁵ - 7.2 10⁻⁵ = 8.1 10⁻⁶ / r₁

-3.96 10⁻⁵ = 8.1 10⁻⁶ / r₁

r₁ = 8.1 10⁻⁶ /3.96 10⁻⁵

r₁ = 2.045 10⁻¹ m

r₁ = 20.5 cm

4 0

3 years ago