Question

A ball is dropped from a building taking 3sec to fall to the ground. Calculate:

Answer 1

Answer:

Vf = 29.4 m/s

h = 44.1 m

Explanation:

Data:

• Initial Velocity (Vo) = 0 m/s
• Gravity (g) = 9.8 m/s²
• Time (t) = 3 s
• Final Velocity (Vf) = ?
• Height (h) = ?

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Final Velocity

Use formula:

• Vf = g * t

Replace:

• Vf = 9.8 m/s² * 3s

Multiply:

• Vf = 29.4 m/s

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Height

Use formula:

• $\boxed{h=\frac{g*(t)^{2}}{2}}$

Replace:

• $\boxed{h=\frac{9.8\frac{m}{s^{2}}*(3s)^{2}}{2}}$

Multiply time squared:

• $\boxed{h=\frac{9.8\frac{m}{s^{2}}*9s^{2}}{2}}$

Simplify the s², and multiply in the numerator:

• $\boxed{h=\frac{88.2m}{2}}$

It divides:

• $\boxed{h=44.1\ m}$

What is the velocity when falling to the ground?

The final velocity is 29.4 meters per seconds.

How high is the building?

The height of the building is 44.1 meters.