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3 years ago

A bee beats its wings 250 times each second. What is the average time for a single beat of a bee's wing?

Mathematics

2 answers:

Marat540 [252]3 years ago

8 0

I'm not sure, but the average time can be 1/250 seconds.

barxatty [35]3 years ago

4 0

for each second the bee beats its wings 250 times.

we are asked to find the average time taken for a single beat of a bees wing

the time taken for 250 beats - 1 second

average time for a single beat - 1 second/ 250 beats = 1/250 seconds/beat

answer is 0.004 seconds per beat

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Layla emptied out her change jar to buy a new binder for school. She found 147 coins consisting of dimes and nickels that totale

den301095 [7]

Answer:

d + n = 147

0.10d + 0.05n = 11.65

d = 86, n = 61

Step-by-step explanation:

Let

Number of dimes = d

Number of nickels = n

Total coins = 147

Total value = $11.65

d + n = 147 (1)

0.10d + 0.05n = 11.65 (2)

From (1)

d = 147 - n

Substitute d = 147 - n into

0.10d + 0.05n = 11.65

0.10(147 - n) + 0.05n = 11.65

14.7 - 0.10n + 0.05n = 11.65

- 0.10n + 0.05n = 11.65 - 14.7

-0.05n = -3.05

n = -3.05 / -0.05

= 61

n = 61

Substitute n = 61 into

d + n = 147

d + 61 = 147

d = 147 - 61

d = 86

6 0

3 years ago

Simplify 4x+5/6x^2-x-12 subtract 5x/6x^2-x-12

neonofarm [45]

4x+5/6x^2-x-12 - (5x/6x^2-x-12)
= (4x + 5 - 5x)/(6x^2-x-12)
= (-x + 5) / (2x - 3)(3x +4)

answer

-x + 5
---------------------
 (2x - 3)(3x +4)

7 0

3 years ago

Solve using long division Please

madreJ [45]

1. $Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}$

$Steps:$

$\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}$

$\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}$

$\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}$

$\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}$

$\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}$

2. $Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}$

$Steps:$

$\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}$

$\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}$

$\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

4 0

3 years ago

Round 14,445 to the nearest hundred

Bumek [7]

Answer:

the answer is 14,400

Step-by-step explanation:

7 0

2 years ago

A bakery sells 3 muffins for every 5 pizza pies. The bakery sold a total of 24 muffins and pizza pies together. How many of each

MariettaO [177]

3+5=8 24÷8=3
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I hope this helped!!!:)

5 0

4 years ago

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