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2 years ago

I think of a number multiply it by two subtract 5 and multiply the result by 3

Mathematics

1 answer:

Semmy [17]2 years ago

7 0

Answer:

Step-by-step explanation:

You could do 40 x 2 = 80 - 5 = 75 x 3 = 225

So if this is right, The answer would be 225

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If you can answer 10, 11, and 12 for me that would be awesome. (12 multiply choice would be in the comments)

fenix001 [56]

10: 3
11: 2
and can’t see 12

5 0

3 years ago

One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

See attachment for possibility tree

Solving (b): The total number of outcome

For urn 1

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

For urn 2

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

5 0

3 years ago

Refer to the triangle below. If a = 4 and b = 6, solve for c. show work Also, give the unsimplified radical form answer and then

9966 [12]

Look at the image below where I labeled the sides

To solve this you must use Pythagorean theorem:

$a^{2} +b^{2} =c^{2}$

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 4

b = 6

c = unknown

^^^Plug these numbers into the theorem

$4^{2} +6^{2} =c^{2}$

simplify

16 + 36 = $x^{2}$

52 = $x^{2}$

To remove the square from x take the square root of both sides to get you...

√52 = x

^^^Unsimplified radical

2√13

^^^Simplified radical

7.21

^^^Rounded to hundedths

Hope this helped!

~Just a girl in love with Shawn Mendes

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3 years ago

How many degrees is one rotation that will put a regular pentagon back on top of itself?

Dmitriy789 [7]

If you rotate about the circumcentre of a regular polygon 72° it will overlap with the original image.

8 0

3 years ago

How to change .365 to a percent

KATRIN_1 [288]

Multipl .365 by 100 and you get 36.5%

3 0

3 years ago

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