All categories

3 years ago

What are some of the major pieces of evidence for the theory of plate tectonics? How does the theory explain these observations?

Physics

1 answer:

marta [7]3 years ago

3 0

Answer:

evidence:

- fossils found in different parts of the world were the same

- weather patterns in different parts of the world

- mountain ranged with the same rock types, structures, and ages are now on opposite sides of the atlantic ocean

- coal was found in cold climates where it could not have formed

-scratches from glaciers were found in a desert

- continents fit like a puzzle

- identical rocks of the same type and age found on both sides of the atlantic ocean

You might be interested in

What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh

Goshia [24]

Answer:

a) $R_s = 0.092$

b) $R_p = 0.085$

Explanation:

given,

n =1.5 for glass surface

n = 1 for air

incidence angle = 45°

using Fresnel equation of reflectivity of S and P polarized light

$R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2$

using snell's law to calculate θ t

$sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}$

$cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}$

a) $R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2$

$R_s = 0.092$

b) $R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2$

$R_p = 0.085$

3 0

3 years ago

Why do animals use echolocation? Check all that apply.

jenyasd209 [6]

To find food to find each other and to find their way

7 0

4 years ago

Read 2 more answers

Two charges are separated by a certain distance. If the magnitude of each charge and the distance are both doubled, the force

ycow [4]

Doubled I think i’m not sure tho

3 0

3 years ago

Suppose you have a glider and a hanging mass that you wish to know the masses of but you do not have a triple-beam balance avail

AlladinOne [14]

Answer:

the choice of a glider to hanging mass is a ratio of 20.2

Explanation:

The Newton´s second law for glider is:

Fnet=Ma

T=Ma

The Newton´s second law for hanging mass is:

Fnet=ma

mag-T=ma

Replacing:

mag-Ma=ma (eq. 1)

Clearing a:

a=(mg)/(m+M)

The expression for motion is:

$y=vot+\frac{1}{2}at^{2}$

$H=0+\frac{1}{2}at^{2}$

Clearing a:

$a=\frac{2H}{t^{2} }$

Replacing values:

$a=\frac{2*0.75}{1.8^{2} } =0.46$

From eq. 1:

M/m=20.2

5 0

3 years ago

Please help me guys never mind the calculations

vlada-n [284]

The shape is connected in parallel so;

5.1) Ans;

$\frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} \\ \frac{1}{R} = \frac{1}{2} + \frac{1}{3} \\ \frac{1}{R} = \frac{3 + 2}{6} = \frac{5}{6} \\ R = \frac{6}{5} = 1.2 \: \: ohm$

5.2) Ans;

$\frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} \\ \frac{1}{R} = \frac{1}{8} + \frac{1}{10} \\ \frac{1}{R} = \frac{5 + 4}{40} = \frac{9}{40} \\ R = \frac{40}{9} = 4.4 \: \: ohm$

I hope I helped you^_^

7 0

3 years ago