Question

What is the force exerted on a moving charge of –2.0 μC at a 20° angle through a magnetic field of 3.0 × 10–4 T with a velocity of 5.0 × 106 m/s?

Answer 1

Answer:

The force exerted on a moving charge is $1.02\times 10^{-3}\ N$.                

Explanation:

We have,

Charge, $q=-2\ \mu C$

Magnetic field, $B=3\times 10^{-4}\ T$

Velocity of charged particle, $v=5\times 10^6\ m/s$

Angle through the magnetic field, $\theta=20^{\circ}$

It is required to find the force exerted on a moving charge. Due to the motion in charge, magnetic force acts on it. It can be given by :

$F=qvB\sin\theta$

Plugging all values above

$F=-2\times 10^{-6}\times 5\times 10^6\times 3\times 10^{-4}\times \sin (20)\\\\F=1.02\times 10^{-3}\ N$

So, force exerted on a moving charge is $1.02\times 10^{-3}\ N$.