Kinetic energy =(1/2) (mass) (speed²)
First object: KE = (1/2) (2 kg) (2m/s)² = 4 joules during the lift.
Second object: KE = (1/2) (4kg) (3 m/s)² = 18 joules during the lift.
The second object has more kinetic energy while it's being lifted
than the first object has while it's being lifted. Once they reach their
final heights and stop, neither object has any kinetic energy.
Explanation:
you can see this example to undersranding the question
Answer:
R = ½ R₀
Explanation:
This is an exercise in Ohm's law,
V = IR
in the initial case
V₀ = I₀ R₀ (1)
indicates that the voltage remains constant and the current is doubled
I = 2 I₀
V₀ = I R
we substitute
V₀ = 2 I₀ R
R = ½ V₀ / I₀
we replace by equation 1
R = ½ R₀
