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stira [4]
3 years ago
15

Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and range. y=-0.5x^2+0.7x-5.1

Mathematics
2 answers:
lianna [129]3 years ago
8 0

Answer:

The domain of the equation is all real number and the range of the equation is (-∞,-4.885].

Step-by-step explanation:

The given quadratic equation is

y=-0.5x^2+0.7x-5.1

Use a graphing calculator to sketch the graph of the quadratic equation.

The graph of given quadratic equation is shown below.

From the graph it is clear that it is a downward parabola and the vertex of the parabola is (0.7,-4.885).

The function is defined from all values of x, therefore the domain of the function is all real number.

The vertex of the parabola is (0.7,-4.885). It means the maximum value of the function is -4.885 and the value of y cannot be more than -4.885.

So, the range of the function is

Range=\{y|y\leq -4.885\}

Therefore the domain of the equation is all real number and the range of the equation is (-∞,-4.885].

blsea [12.9K]3 years ago
4 0
The graph below is on the scale of five and I hope it is helpful.

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Autos de F 1. En un circuito de Australia, Hamilton hizo el récord de vuelta. Si lo normal a 240km/h para completar el circuito
olga2289 [7]

Answer:

Tenía que hacerlo en menos de 2 minutos a más de 240 km/h

Step-by-step explanation:

La velocidad normal dada para completar el circuito de 6.000 metros = 240 km/h

El tiempo normal que se tarda en completar el circuito de 6000 metros = 2 minutos

Dado que Hamilton estableció el récord de vuelta, el tiempo que tuvo que hacer para recorrer el récord de vuelta es de 6000 metros en menos de 2 minutos

La velocidad media con la que lo hizo es de más de 240 km/h.

6 0
3 years ago
In 2013, the moose population in a park was measured to be 5,100. By 2018, the population was measured again to be 5,200. If the
natka813 [3]

Answer:

P(t) = 5100e^{0.0039t}

Step-by-step explanation:

The exponential model for the population in t years after 2013 is given by:

P(t) = P(0)e^{rt}

In which P(0) is the population in 2013 and r is the growth rate.

In 2013, the moose population in a park was measured to be 5,100

This means that P(0) = 5100

So

P(t) = 5100e^{rt}

By 2018, the population was measured again to be 5,200.

2018 is 2018-2013 = 5 years after 2013.

So this means that P(5) = 5200.

We use this to find r.

P(t) = 5100e^{rt}

5200 = 5100e^{5r}

e^{5r} = \frac{52}{51}

\ln{e^{5r}} = \ln{\frac{52}{51}}

5r = \ln{\frac{52}{51}}

r = \frac{\ln{\frac{52}{51}}}{5}

r = 0.0039

So the equation for the moose population is:

P(t) = 5100e^{0.0039t}

5 0
3 years ago
Will mark brainliest and thank you!!! Please help!
Usimov [2.4K]
The correct answer is maybe 3
7 0
3 years ago
Can somebody tell me what's 43 divided by 1032 in long division? (Step by step) Or send a picture please
Brut [27]

Answer:

24

Step-by-step explanat

Divide both the numerator and denominator by the GCD

1032 ÷ 43

43 ÷ 43

Reduced fraction:

24

1

Therefore, 1032/43 simplified to lowest terms is 24/1.

5 0
3 years ago
Help please help I don’t know this
Ganezh [65]

Answer:

option d is the correct answer.

Step-by-step explanation:

3 0
3 years ago
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