<span>We use the Pythagoras Theorem to derive a formula for finding the distance
between two points in 2- and 3- dimensional space.</span>
Let
P<span> = (x 1, y 1) </span>
Q<span> = (x 2, y 2) </span>
be two points on the Cartesian plane
<span>Then
from the Pythagoras Theorem we find that the distance between P and Q is</span>
PQ=((x2-x1)^2+(y2-y1)^2)^0.5
In a
similar way
it can
be proved that if
P<span> = (x 1, y 1, z1) and </span>
Q<span> = (x 2, y 2, z2) are two
points in the 3-dimensional space, </span>
<span>the
distance between P and Q is</span>
PQ=((x2-x1)^2+(y2-y1)^2+(z2-z1)^2)^0.5
<span>
</span>
Answer:
$11,130.47
Step-by-step explanation:
The amortization formula can be used. It tells you the monthly payment amount A for some principal P, interest rate r, and n payments.
A = P(r/12)/(1 -(1 +r/12)^(-n))
Filling in your values, we get ...
200 = P(.03/12)/(1 -(1 +.03/12)^-60) = P(.0025)/(1 -1.0025^-60)
P = 200(1 -1.0025^-60)/.0025 ≈ 200×55.6523577
P ≈ 11,130.47
The present value of the loan is $11,130.47.
The answer to = 2x27 is f(x)
