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MrRa [10]
3 years ago
6

Help??

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

2.58g

Explanation:

First calculate the moles of butane used in the reaction

moles = mass÷molar mass

= 0.85÷58

= 0.0147

According to the stoichiometric ratio:

C4H10 : CO2 = 2:8

moles of CO2 =(8÷2)×0.0147

=0.0586 moles

mass of CO2 = 0.0586×44

= 2.58g

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