Question

3. A 0.300 g of gas Y at 3.00 atm was filled in a flask with a volume of 82.0 ml. Calculate

Answer 1

Answer:

Calculate the volume of gas and then you have ur answer

Explanation:

Answer 2

The new volume of gas Y is 89.38 mL

From the question given above, the following data were obtained:

Initial volume (V₁) = 82.0 mL

Initial temperature (T₁) = 27.0 °C = 27 + 273 = 300 K

Final temperature (T₂) = 54.0 °C = 54 + 273 = 327 K

Pressure = 3 atm = constant

Final volume (V₂) =?

Since the pressure is constant, we shall determine the final volume of gas Y using the Charles' law equation as follow:

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}} \\\\\frac{82}{300} = \frac{V_{2}}{327}$

Cross multiply

300 × V₂ = 82 × 327

300 × V₂ = 26814

Divide both side by 300

$V_{2} = \frac{26814}{300}$

V₂ = 89.38 mL

Therefore, the new volume of gas Y is 89.38 mL

Learn more: brainly.com/question/12835309