Answer:
What's the function? Put the function in the problem so I can solve.
Step-by-step explanation:
Step-by-step explanation:
y=3x+1, y= -3x+7
y=1,X=1
X+y=10,2x+2y=20
X=5, y=5
Answer:
Step by step explanation:
![y=\displaystyle \int_{0}^x 2t^2 dt=\dfrac 23\left[t^3\right]^{x}_0=\dfrac 23 x^3\\\\\ y'= \dfrac 23 \cdot 3x^2 = 2x^2](https://tex.z-dn.net/?f=y%3D%5Cdisplaystyle%20%5Cint_%7B0%7D%5Ex%202t%5E2%20dt%3D%5Cdfrac%2023%5Cleft%5Bt%5E3%5Cright%5D%5E%7Bx%7D_0%3D%5Cdfrac%2023%20x%5E3%5C%5C%5C%5C%5C%20y%27%3D%20%5Cdfrac%2023%20%5Ccdot%203x%5E2%20%3D%202x%5E2)
Answer:
x = 8.0
Step-by-step explanation:
Since the triangle is right use the cosine ratio to solve for x
cos37° = 
= 
Cross- multiply
x = 10 × cos37° ≈ 8.0 ( to the nearest tenth )
Answer:
y = - x + 4
Step-by-step explanation:
The first step is to find the slope-intercept form, which is:
y=x-6.
Then, y=x+6
y=-x+4 should be the answer since it passes through the point (-1, 5)
