Answer:
The answer to the given question is "yes".
Explanation:
In the programming language, Protected is a keyword that is used as an access modifier by using protected members we only access within the same class and it also provides access to use this member in the derived class that is inherited by derived class from the base class.
That's why the answer to this question is "yes".
Answer:
What is the use of metering in camera?
Metering is used to measure the brightness of the subject. The camera optimizes exposure by adjusting shutter speed, aperture (f-number), and ISO sensitivity according to the brightness of the subject, which is measured using the camera's built-in metering sensor.
Explanation:
If the answer is right Can you mark me as brainliest if you can?
Answer:
here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// function to alphabetize the input string
void alphabetize(string &str)
{
// find the length of string
int n=str.size();
for(int x=0;x<n;x++){
for(int y=x+1;y<n;y++)
{
//swap the character
if(str[x]>str[y]){
char ch=str[x];
str[x]=str[y];
str[y]=ch;
}
}
}
cout<<"alphabetize string is: "<<str<<endl;;
}
int main()
{// string variable to read input
string inp;
cout<<"Please Enter a String in lowercase :";
//reading the input
cin>>inp;
// call function with inp argument
alphabetize(inp);
return 0;
}
Explanation:
Declare a variable "inp" of string type and assign the input string to it. call the alphabetize() function with argument "inp".In the alphabetize(),find the length of input string.Then travers the string and if a character is greater than any next character in the string then swap it, so that all the character are sorted.
Output:
Please Enter a String in lowercase :helloworld
alphabetize string is: dehllloorw
Whatever energy the electrons have when they come out of one terminal of the battery, they completely use it up on their way around the circuit, and they stagger back into the other terminal of the battery totally exhausted, with no energy left.
If each coulomb of electrons has 6 joules of energy when they leave the battery, then that's the energy they'll give up to the circuit before they return to the battery.
For each coulomb of charge that moves through that circuit, each flashlight bulb
will take 3 joules of energy away from that coulomb, and turn the energy into heat
and light.
==> 2 bulbs, 3 joules per coulomb that flows through each bulb, total 6 joules
per coulomb that flows around the circuit.
Note:
The question says that the bulbs are in series, but that wasn't necessary.
The energy consumed by the bulbs would be the same if they're in parallel.
A cool extra factoid:
The battery gives each coulomb of electrons that leaves it 6 joules of energy.
There's a special name for "1 joule per coulomb of charge". That's the "<em>volt</em>".
A battery that gives each coulomb of charge 6 joules of energy is a 6-volt battery.