Answer:
From a hardware standpoint, the CPU is most likely the main component. From a software standpoint, macOS and Windows are complex software systems.
Explanation:
VLAN refers to Virtual Local Area Network. It is a subnetwork that can group together collection of devices on separate physical Local Area Networks. VLANs allow network administrators to group hosts together even if the hosts are not directly connected to the same network switch.
Considering the large number of departments in hospitals, with each departments having functions different from the others, Virtual LANs allows various users(the departments) to be grouped together according to their networking needs, regardless of their actual physical locations. Subdividing the LAN into smaller segments, or VLANs, increases overall reliability, security, and performance, and makes the network easier to maintain.
Because of the largeness of St. Luke's hospitals and their mission of delivering highly reliable and feature-rich advanced network solutions, virtual LAN will help to provide a resilient and scalable network solution within the hospital's budget.
St. Luke should implement virtual LAN that can produce a higher bandwidth with lower-cost, a longer-term model based on servers, networking products and homogenous network components to deliver centralized management of computing across the hospital network.
Answer:
See explanation below
Explanation:
Previos concepts
First Come First Serve (FCFS) "is an operating system scheduling algorithm that automatically executes queued requests and processes in order of their arrival".
Shortest job next (SJN), or the shortest job first (SJF) or shortest "is a scheduling policy that selects for execution the waiting process with the smallest execution time".
Shortest remaining time (SRF) "is a scheduling method that is a preemptive version of shortest job next scheduling'".
Round robin (RR) is an algorithm where the time parts "are assigned to each process in equal portions and in circular order, handling all processes without priority"
Solution for the problem
Assuming the dataset given on the plot attached.
Part a
For this algorithm the result would be:
Job A 0-6
Job B 6-(6+3) = 6-9
Job C 9-(9+1) = 9-10
Job D 10-(10+4) = 10-14
Part b
For this algorithm the result would be:
Job A 0-6
Job C 6-(6+1) = 6-7
Job B 7-(7+3) = 7-10
Job D 10-(10+4) = 10-14
Part c
For this algorithm the result would be:
Job A 0-1 until 14
Job B 2-(2+3) = 2-5
Job C 3-(3+2) = 3-5
Job D 9-(9+5) = 9-14
Part d
For this algorithm the result would be:
Job A 0-2 , 7-9, 12-14
Job B 2-4, 9-10
Job C 4-(4+1) = 4-5
Job D 5-7, 10-12
You can construct it with a protractor.