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Given:
Street C is perpendicular to Street A and passes through (4, -6).
The equation of street A is:
To find:
The equation of street C.
Solution:
The equation of street A is:
On comparing this equation with slope intercept form , we get
Slope of this line is -2.
We know that, the product of slopes of two perpendicular lines is always -1.
The slope of street C is and it passes through the point (4,-6). So, the equation of street C is
Therefore, the point slope form of the street C's equation is .