Hi there!
If you run into problems like this, remember to "Stay calm and find the common denom." That just means find the common denominator.
13/35 and 2/5 = 13/35 and 14/35
As you can tell, 2/5 is larger.
Hope this helps.
:)
Answer:
Approximately 12.04 units.
Step-by-step explanation:
The find the distance between any two points, we can use the distance formula, which is:

We have the points (2,7) and (-6,-2). Let's let (2,7) be (x₁, y₁) and let's let (-6, -2) be (x₂, y₂). Substitute:

Subtract:

Square:

Add:

Approximate

So, the distance between (2,7) and (-6,-2) is approximately 12.04 units.
And we're done!
Answer:
Step-by-step explanation: Explanation:
If
L
,
H
and
W
represent the length, height and width of the prism, then the volume of the rectangular prism is :
V
=
L
.
H
.
W
............. (1)
Given :
V
=
x
3
+
11
x
2
+
20
x
−
32
;
............... (2)
W
=
(
x
−
1
)
;
H
=
(
x
+
8
)
.
Let
L
=
(
x
+
l
0
)
be the expression for the length, then the RHS of equation (1) becomes
L
.
H
.
W
=
(
x
−
l
0
)
(
x
+
8
)
(
x
−
1
)
,
=
(
x
+
l
0
)
(
x
2
+
7
x
−
8
)
=
(
x
+
l
0
)
(
x
2
+
7
x
−
8
)
=
x
3
+
(
7
+
l
0
)
x
2
+
(
7
l
0
−
8
)
x
−
8
l
0
..... (3)
Comparing this to the LHS of equation (1), we get the following set of equations to solve for
l
0
,
7
+
l
0
=
11
;
7
l
0
−
8
=
20
;
8
l
0
=
32
;
l
0
=
4
Therefore
L
=
(
x
+
4
)
Answer:
K = 10
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin theta = opp/ hyp
sin K = 11 / 61
Taking the inverse sin of each side
sin ^-1 ( sin K) = sin ^-1 (11/61)
K =10.38885782
K = 10
Answer:
Option B is correct .
Step-by-step explanation:
According to Question , both the graph have same shape . If we look at the the first graph it cuts x - axis at (0 , 2) and ( 0 , -2) . Hence x = 2 and -2 are the zeroes of the equation .
And ,the given function is ,
<u>Hence ,we can can see that x = </u><u> </u><u>2</u><u> </u><u>and</u><u> </u><u>(</u><u>-</u><u>2</u><u>)</u><u> </u><u>are</u><u> </u><u>the</u><u> </u><u>zeroes </u><u>of </u><u>graph</u><u>. </u><u> </u>
This implies that if we know the zeroes , we can frame the Equation.
On looking at second parabola , it's clear that cuts x - axis at ( 1, 0 ) and (-1,0). So , 1 and -1 are the zeroes of the quadratic equation . Let the function be g(x) . Here , a and ß are the zeroes.
<u>Hence </u><u>option </u><u>B</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u>